将字符串中的重复字符减少到给定的最小值 [英] Reducing duplicate characters in a string to a given minimum

问题描述

我在这里解决第一个问题：将重复的字符减少到所需的最低限度，我正在寻找比我想象的更优雅的答案。它通过测试，但好奇看到其他解决方案。样本测试是：

I was messing around with the first question here: Reduce duplicate characters to a desired minimum and am looking for more elegant answers than what I came up with. It passes the test but curious to see other solutions. The sample tests are:

reduceString('aaaabbbb', 2) 'aabb'  
reduceString('xaaabbbb', 2) 'xaabb' 
reduceString('aaaabbbb', 1) 'ab'    
reduceString('aaxxxaabbbb', 2)  'aaxxaabb'

和我的解决方案（通过这些测试）：

and my solution (that passes these tests):

reduceString = function(str, amount) {
  var count = 0;
  var result = '';
  for (var i = 0; i < str.length; i++) {
    if (str[i] === str[i+1]) {
      count++;
      if (count < amount) {
        result += str[i];
      }
    } else {
      count = 0;
      result += str[i];
    } 
  };
  return result;
}

推荐答案

只需使用正则表达式。

Just use regular expressions.

var reduceString = function (str, amount) {
    var re = new RegExp("(.)(?=\\1{" + amount + "})","g");
    return str.replace(re, "");
}

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