或者在if语句中使用操作数 [英] Or operand with int in if statement

问题描述

我有

我的问题是程序没有正在阅读代码， pre> if（hero.getPos（）==（6 | 11 | 16））{
move = new Object [] {Up，Right，Left };
} else {
move = new Object [] {Up，Down，Right，Left};
}


当英雄位置为6时，程序仍然转到其他。 >

为什么？是因为操作数吗？如果是，我该如何改变？

解决方案

使用：

< p $ p> if（hero.getPos（）== 6 || hero.getPos（）== 11 || hero.getPos（）== 16））{


这将做你想要的。

你所做的是比较 hero.getPos（），其结果为（6 | 11 | 16）将执行这些数字之间的位置或。

My problem is that program is not reading codes as i intended "he" would.

I have

if (hero.getPos() == (6 | 11 | 16)) {
    move = new Object[] {"Up", "Right", "Left"};
} else {
    move = new Object[] {"Up", "Down", "Right", "Left"};
}

When hero position is 6, the program still goes to else.

Why is that? Is it because of operands? If yes, how should i change it?

解决方案

Use:

if (hero.getPos() == 6 || hero.getPos() == 11 || hero.getPos() == 16)) {

This will do what you want.

What you did is comparing hero.getPos() with the result of (6|11|16) which will do bitwise or between those numbers.

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