PHP类继承深度 [英] PHP class inheritance depth

问题描述

例如，如果我从A类开始

类扩展A类

Class C扩展类B

D类扩展类C

Class E扩展D类

类F扩展E类

类G扩展F类

大部分较低级别是抽象类，方法填充代码和抽象方法。它是一个相当大而复杂的结构。 （做我的头）

G类仍然可以访问A类方法和参数，以及仍然可以访问A类的抽象方法？ / p>

我问，因为我已经遇到了eclipse的麻烦，没有将较低级的方法添加到自动完成。我想知道实际上是否有限制，或者是否只是日食达到代码完成的最大值。

我远离我可以测试这个与我已经做了什么，不想找到什么时候我完成那些方法定义较低的顺序是不可访问的。

解决方案

听起来像编辑器的问题。例如，请参阅以下快速和肮脏的演示：

  php> class a {function foo（）{echoA :: foo（）\\\
; }} 
 php> $ letters = range（'a'，'z'）; 
 php> for（$ i = 0; $ i< 25; $ i ++）{eval（class {$ letters [$ i + 1]} extends {$ letters [$ i]} {}）; } 
 php> $ z = new z; 
 php> $ Z-> FOO（）; 
 A :: foo（）
  

PHP不会施加任何类似的限制在你身上。

I'm trying to work out exactly how deep inheritance goes.

For example if I start with class A

Class B extends class A
Class C extends class B
Class D extends class C
Class E extends class D
Class F extends class E
Class G extends class F

most of the lower levels are abstract classes with methods filled with code and abstract methods. its a rather large and complex structure. (doing my head in)

Will Class G still be able to access Class A methods and parameters, as well as still have access to the abstract methods from Class A ?

I'm asking because I have been having trouble with eclipse not adding the lower class methods into the auto complete. I would like to know if there is actually a limit to this or whether it's just eclipse reaching its maximum for code completion.

I'm far from a stage where I can test this with what I have done and don't want to find when I'm done that methods defined lower in the order are not accessible.

解决方案

Sounds like a problem with your editor. For example, see the following quick-and-dirty demonstration:

php > class a { function foo() { echo "A::foo()\n"; } }
php > $letters = range('a', 'z');
php > for ($i = 0; $i < 25; $i++) { eval("class {$letters[$i+1]} extends {$letters[$i]} {}"); }
php > $z = new z;
php > $z->foo();
A::foo()

PHP doesn't impose any kind of restriction like this on you.

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