使用< a href =">>从servler重定向到另一个servlet doGet（）方法 [英] Redirect from one servlet to another from the servler doGet() method using <a href="">

问题描述

我有一个问题，如何从启动的servlet正文（doGet（）或doPost（））重定向到另一个servlet站点？

第一个servlet：

  public class StartingServlet extends HttpServlet 
 {
 private static final long serialVersionUID = 1L; 
 
 protected void doGet（HttpServletRequest request，HttpServletResponse response）throws ServletException，IOException 
 {
 PrintWriter out = response.getWriter（）; 
 out.println（Strona startowa）; 
 // String go =http：// localhost：8080 / HelloWorld / test; 
 // response.sendRedirect（response.encodeRedirectURL（go））; 
 out.println（< a href =http：// localhost：8080 / HelloWorld / test> Hello World Servlet< / a>）; 
} 
 
} 
  

第二个servlet想要继续点击链接）：

  public class HelloWorldServlet extends HttpServlet 
 {
 
 private static final long serialVersionUID = 1L; 
 
 protected void doGet（HttpServletRequest request，HttpServletResponse response）throws ServletException，IOException 
 {
 PrintWriter out = response.getWriter（）; 
 out.println（Hello World Servlet）; 
 
} 
} 
  

web.xml文件（servlet-启动servlet的映射url-pattern目的是空的）：

 <？xml version =1.0encoding = UTF-8\" >？; 
< web-app xmlns：xsi =http://www.w3.org/2001/XMLSchema-instancexmlns =http://java.sun.com/xml/ns/javaeexsi ：schemaLocation =http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsdid =WebApp_IDversion =3.0 > 
< display-name> HelloWorld< / display-name> 
< welcome-file-list> 
< welcome-file> index.html< / welcome-file> 
< welcome-file> index.htm< / welcome-file> 
< welcome-file> index.jsp< / welcome-file> 
< welcome-file> default.html< / welcome-file> 
< welcome-file> default.htm< / welcome-file> 
< welcome-file> default.jsp< / welcome-file> 
< / welcome-file-list> 
 
< servlet> 
< servlet-name>启动servlet< / servlet-name> 
< servlet-class> pl.javastart.servlets.StartingServlet< / servlet-class> 
< / servlet> 
 
< servlet-mapping> 
< servlet-name>启动servlet< / servlet-name> 
< url-pattern>< / url-pattern> 
< / servlet-mapping> 
 
< servlet> 
< servlet-name> Hello World Servlet< / servlet-name> 
< servlet-class> pl.javastart.servlets.HelloWorldServlet< / servlet-class> 
< / servlet> 
 
< servlet-mapping> 
< servlet-name> Hello World Servlet< / servlet-name> 
< url-pattern> / test< / url-pattern> 
< / servlet-mapping> 
 
< / web-app> 
  

我该怎么做？
提前谢谢。

解决方案

要从servlet重定向请求，您可以使用 sendRedirect 方法：

  response.sendRedirect（http：// localhost：8080 / HelloWorld / test ）; 
  

Btw这句话：

  out.println（< a href =http：// localhost：8080 / HelloWorld / test> Hello World Servlet< / a>）; 
  

只需在响应正文中发送链接，但不会重定向。

Hi I have a question how to redirect from starting servlet body(doGet() or doPost()) to another's servlet site?

First servlet:

public class StartingServlet extends HttpServlet 
{
private static final long serialVersionUID = 1L;

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException,IOException
    {
    PrintWriter out=response.getWriter();
    out.println("Strona startowa");
//      String go  ="http://localhost:8080/HelloWorld/test";        
//      response.sendRedirect(response.encodeRedirectURL(go));
        out.println("<a href="http://localhost:8080/HelloWorld/test"> Hello World Servlet </a>");
    }

}

Second servlet(the one that i want to go after i click on link):

public class HelloWorldServlet extends HttpServlet
{

    private static final long serialVersionUID = 1L;

    protected void doGet(HttpServletRequest request,HttpServletResponse response)throws ServletException,IOException
    {
        PrintWriter out= response.getWriter();
        out.println("Hello World Servlet");

    }
}

web.xml file(servlet-mappings url-pattern for the starting servlet is empty on purpose):

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>HelloWorld</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>

  <servlet>
    <servlet-name>Starting servlet</servlet-name>
    <servlet-class>pl.javastart.servlets.StartingServlet</servlet-class>
  </servlet>

  <servlet-mapping>
    <servlet-name>Starting servlet</servlet-name>
    <url-pattern></url-pattern>
  </servlet-mapping>

  <servlet>
    <servlet-name>Hello World Servlet</servlet-name>
    <servlet-class>pl.javastart.servlets.HelloWorldServlet</servlet-class>
  </servlet>

  <servlet-mapping>
    <servlet-name>Hello World Servlet</servlet-name>
    <url-pattern>/test</url-pattern>
  </servlet-mapping>

</web-app>

How do I do that? Thank you in advance.

解决方案

To redirect a request from servlet you can use sendRedirect method :

    response.sendRedirect("http://localhost:8080/HelloWorld/test");

Btw this statement:

out.println("<a href="http://localhost:8080/HelloWorld/test"> Hello World Servlet </a>");

will simply send the link in response body but will not redirect.

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