如何删除匹配模式的整行 [英] How to remove an entire line which matches a pattern

问题描述

以下模式与整行相匹配，如何搜索和删除这些行。如果我在替换字符串中留下一个空格，那么当我通过eclipse执行时，它留下一条空白。

The following pattern matches an entire line, how do I search and remove these lines. If I leave a space in the replace string, it leaves a blank in that particular line, when I do via eclipse.

^[\t ]*<param name="logic" .*$

推荐答案

我不知道有关eclipse的任何内容，但您可能需要包含 \\\
换行符，才能完全删除该行。另外 - 可以用空字符串代替空格吗？

I don't know anything about eclipse but you may need to include the \n newline match in order to remove the line completely. Also - is it possible to replace with an empty string as opposed to a space?

^[\t ]*<param name="logic" .*\n$

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