RESTLET GAE ECLIPSE初始化方法 [英] RESTLET GAE ECLIPSE initializate method

问题描述

我正在使用Restlet，GAE和Eclipse开发一个应用程序。 Oks，我得到了：

public class MainRestletApplication extends Application {

  public MainRestletApplication（）
 {
 // init code？ 
} 
 
 
 @Override 
 public Restlet createInboundRoot（）{
路由器路由器=新路由器（getContext（））; 
 
 router.attach（/ v1 / mainstatus，MainStatus.class）; 
 router.attach（/ v1 / game / {id} / result，GameResult.class）; 
 
返回路由器; 
} 
  

}

这个：

 < servlet> 
< servlet-name> RestletServlet< / servlet-name> 
< servlet-class> org.restlet.ext.servlet.ServerServlet< / servlet-class> 
< init-param> 
< param-name> org.restlet.application< / param-name> 
< param-value> com.example.MainRestletApplication 
< / param-value> 
< / init-param> 
< / servlet> 
 
<！ - 捕获所有请求 - > 
< servlet-mapping> 
< servlet-name> RestletServlet< / servlet-name> 
< url-pattern> / *< / url-pattern> 
< / servlet-mapping> 
  

---

嗯，在哪里可以把一个方法放到init Web服务，ergo，一些代码只有当应用程序启动（一次）才能初始化一些数据，而不是当第一个呼叫进入时。

谢谢

解决方案

您是否使用Restlet或者不使用AppEngine，您可以在web.xml中的任何servlet环境中设置上下文侦听器，如下所示： / p>

 < listener> 
< listener-class> 
 example.ServletContextExample 
< / listener-class> 
< / listener> 
  

并实现此;

  public class ServletContextExample实现ServletContextListener {
 ServletContext context; 
 public void contextInitialized（ServletContextEvent contextEvent）{
 System.out.println（Context Created）; 
 context = contextEvent.getServletContext（）; 
 //将变量设置为servlet上下文
 context.setAttribute（TEST，TEST_VALUE）; 
} 
 public void contextDestroyed（ServletContextEvent contextEvent）{
 context = contextEvent.getServletContext（）; 
 System.out.println（Context Destroyed）; 
} 
} 
  

当您的GAE上的实例启动时，将在执行呼叫之前执行;另一方面，一个新的实例很可能是因为必须处理一个调用而启动的。鸡和鸡蛋故事...

I'm developing an application with Restlet, GAE and Eclipse. Oks, I got this:

public class MainRestletApplication extends Application {

public MainRestletApplication()
{
//init code?
} 


@Override
public Restlet createInboundRoot() {
    Router router = new Router(getContext());

    router.attach("/v1/mainstatus",MainStatus.class);
    router.attach("/v1/game/{id}/result",GameResult.class);

    return router;
}

}

and this:

<servlet>
    <servlet-name>RestletServlet</servlet-name>
    <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
    <init-param>
        <param-name>org.restlet.application</param-name>
        <param-value>com.example.MainRestletApplication
        </param-value>
    </init-param>
</servlet>

<!-- Catch all requests -->
<servlet-mapping>
    <servlet-name>RestletServlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

---

Well, where can I put a method to init the Web Service, ergo, some code to init some data only when the app starts (one time), not when the first call coming.

Thanks

解决方案

wether you use Restlet or not, AppEngine or not, you can setup a context listener in any servlet environment in your web.xml like this :

<listener>
    <listener-class>
        example.ServletContextExample
    </listener-class>
</listener>

And implement this ;

public class ServletContextExample implements ServletContextListener{
    ServletContext context;
    public void contextInitialized(ServletContextEvent contextEvent) {
        System.out.println("Context Created");
        context = contextEvent.getServletContext();
        // set variable to servlet context
        context.setAttribute("TEST", "TEST_VALUE");
    }
    public void contextDestroyed(ServletContextEvent contextEvent) {
        context = contextEvent.getServletContext();
        System.out.println("Context Destroyed");
    }
}

When your instance on GAE is started, the init code will be executed, before a call is processed; on the other hand, a new instance is most likely started because a call must be processed. chicken and egg story...

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