从jar文件获取资源 [英] Get resources from a jar file

问题描述

我想要我的jar文件从本身访问一些文件。我知道如何执行 BufferedImage ，但这不适用于其他文件。我想要的是从我的罐子中提取一些拉链。我在eclipse中创建了一个类文件夹，将拉链放在里面并使用

i want my jar file to access some files from itself. I know how to do this for BufferedImage but this doesn't work for other files. All i want is to extract some zips from my jar. i made a class folder in eclipse, put the zips inside and used

    public File getResFile(String name){

    return new File(getClass().getResource(name).getFile());


}

获取文件实例并解压。它在日食中工作正常，但是一旦我将其导出到一个jar，它说

to get the File instance and extract it. it works fine in eclipse, but as soon as i export it to a jar it says

Exception in thread "main" java.io.FileNotFoundException: file:\C:\Users\DeLL\Desktop\BoxcraftClient\ClientInstaller.jar!\client.bxc (The filename, directory name, or volume label syntax is incorrect)
    at java.util.zip.ZipFile.open(Native Method)
    at java.util.zip.ZipFile.<init>(ZipFile.java:220)
    at java.util.zip.ZipFile.<init>(ZipFile.java:150)
    at java.util.zip.ZipFile.<init>(ZipFile.java:164)
    at Launcher.install(Launcher.java:43)
    at Launcher.main(Launcher.java:33)

我正在修复这已经是6个小时了，找不到解决方案。请帮助！

Im working to fix this already something like 6 hours and can't find a solution. Please help!

推荐答案

有一个原因为什么 getResource（）返回一个 URL ，而不是文件，因为资源可能不是并且由于您的代码打包在Jar文件中，它不是一个文件，而是一个zip条目。

There is a reason why getResource() returns a URL, and not a File, because the resource may not be a file, and since your code is packaged in the Jar file, it's not a file but a zip entry.

读取资源内容的唯一安全方法是 InputStream ，通过调用 getResourceAsStream（）或调用 openStream（）在返回的 URL 。

The only safe way to read the content of the resource, is as an InputStream, either by calling getResourceAsStream() or by calling openStream() on the returned URL.

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