使用不是有效变量名称的属性名进行对象解构 [英] Object destructuring with property names that are not valid variable names
本文介绍了使用不是有效变量名称的属性名进行对象解构的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
var obj1 = {名字:史密斯先生,年龄:21岁;
// destructure
var {name,age} = obj1;
// name ='史密斯先生和年龄= 21
这样可以预期。
但是当我有以下对象结构可以使用对象解构吗?
code> var obj2 = {我的名字:琼斯先生,年龄:22};
var {'my name',age} = obj2;
如果这是不可能的,如果我可以使用某种类型的语法'as'...
var {'my name'as name,age} = obj2; // name ='琼斯先生';
谢谢
解决方案
您可以使用以下语法为其分配一个有效的变量名:
var {my name:myName, age} = obj2;
//使用myName这里
Does anyone know if you can use object destructuring with spaces in the property name? Maybe this cannot be done and I realize the JavaScript notation is incorrect but I cannot change the server json response.
var obj1 = {name: 'Mr Smith', age: 21};
//destructure
var {name, age} = obj1;
//name='Mr Smith' and age=21
This works as expected.
But when I have the following object structure can I use object destructuring or not?
var obj2 = {"my name": "Mr Jones", age: 22};
var {'my name', age} = obj2;
If this is not possible It would be nice if I could assign the variable with some sort of syntax like 'as'...
var {'my name' as name, age} = obj2; //name='Mr Jones';
Thanks
解决方案
You can assign it a valid variable name using this syntax:
var {"my name": myName, age} = obj2;
// use myName here
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