ES6：错误的字符转义序列创建ASCII字符串 [英] ES6: Bad character escape sequence creating ASCII string

问题描述

这是我的代码：

  let padded =03; 
 ascii =`\u00 $ {padded}`; 
  

但是，我收到坏字符转义序列来自巴别塔我想要结束：

\\\

在 ascii 变量中。我做错了什么？

编辑：

结束语 ascii = eval（'\\u00'+ padded +''））;

解决方案

我做错了什么？

unicode转义序列基本上是原子的。你不能真正地构建一个动态的。模板文字基本上执行字符串连接，因此您的代码相当于

 '\00'+ padded 
  

现在应该明白为什么你得到这个错误。如果要获取相应的unicode字符，可以使用 String.fromCodePoint 或 String.fromCharCode ：

  String.fromCodePoint（3）
  





---

如果您希望字符串包含字符序列 \\\ 的字符串，那么您只需要转义转义字符即可生成字面反斜杠：

 `\\u00 $ {padded}`
  / pre> 
Here's my code:
let padded = "03";
ascii = `\u00${padded}`;
However, I receive Bad character escape sequence from Babel. I'm trying to end up with:

\u0003

in the ascii variable. What am I doing wrong?

EDIT:

Ended up with ascii = (eval('"\\u00' + padded + '"'));
解决方案

  
What am I doing wrong?
A unicode escape sequence is basically atomic. You cannot really build one dynamically. Template literals basically perform string concatenation, so your code is equivalent to
'\00' + padded
It should be obvious now why you get that error. If you want to get the corresponding unicode character you can instead use String.fromCodePoint or String.fromCharCode:
String.fromCodePoint(3)




If you want a string that literally contains the character sequence \u0003, then you just need to escape the escape character to produce a literal backslash:
`\\u00${padded}`


                        
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