资源下载平滑的色彩过渡 [英] Java Smooth Color Transition

问题描述

比方说，我给出两种颜色。

Let's say I am given two colors.

public final static Color FAR = new Color(237, 237, 30);
public final static Color CLOSE = new Color(58, 237, 221);

我将如何从一种颜色过渡到下一个没有动用暗的颜色？

How would I transition from one color to the next without dipping into dark colors?

我来出主意，如

    double ratio = diff / range; // goes from 1 to 0
    int red = (int)Math.abs((ratio * FAR.getRed()) - ((1 - ratio) * CLOSE.getRed()));
    int green = (int)Math.abs((ratio * FAR.getGreen()) - ((1 - ratio) * CLOSE.getGreen()));
    int blue = (int)Math.abs((ratio * FAR.getBlue()) - ((1 - ratio) * CLOSE.getBlue()));

或

    double ratio = diff / range; // goes from 1 to 0
    int red = (int) ((1 - (diff / range)) * FAR.getRed() + CLOSE.getRed() - FAR.getRed());
    int green = (int) ((1 - (diff / range)) * FAR.getGreen() + CLOSE.getGreen() - FAR.getGreen());
    int blue = (int) ((1 - (diff / range)) * FAR.getBlue() + CLOSE.getBlue() - FAR.getBlue());

但遗憾的是他们没有顺利地从一种颜色到下一个过渡。 请问有谁知道如何做到这一点，同时保持颜色鲜艳，而不是动用较深的颜色，或者如何确保渐变过渡是平滑的，而不是在先慢后快，然后再慢？

But unfortunately none of them smoothly transition from one color to the next. Would anyone know how to do so while keeping the color bright and not dipping into darker colors, or how to ensure that gradient transition is smooth rather than slow at first then fast and then slow again?

我真的不ca的拿出任何公式。

I really ca not come up with any formula.

推荐答案

您使用了错误的标志在calcuations。应加，不减去，以应用比正常。

You're using the wrong sign in the calcuations. Should be plus, not minus, to apply the ratio properly.

int red = (int)Math.abs((ratio * FAR.getRed()) + ((1 - ratio) * CLOSE.getRed()));
int green = (int)Math.abs((ratio * FAR.getGreen()) + ((1 - ratio) * CLOSE.getGreen()));
int blue = (int)Math.abs((ratio * FAR.getBlue()) + ((1 - ratio) * CLOSE.getBlue()));

您也快黑的颜色与你现有的执行情况的原因是，与（ - ），经常会出现下降接近零（？小于50或负但大于-50），并在负的情况下，好了，你正在服用的绝对值，使其成为一个小的正数，即深色。

The reason you are getting dark colours with your existing implementation is that with (-), they would often fall close to zero (less than 50? or negative but greater than -50?) and in the negative case, well, you are taking the absolute value so it becomes a small positive number, i.e. a dark colour.

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