弹性搜索/轮胎：如何映射到关联属性？ [英] Elastic Search/Tire: How to map to association attribute?

问题描述

我正在使用轮胎进行弹性搜索。在我的应用程序中，我有2个模型;价格和产品。

我正在搜索我的Price类，并使用它所属的产品：name 属性为搜索字段。现在，如果我有一个名为 Product 1 并输入pro，prod或duct的产品，则不会显示任何结果。但输入产品或产品显示结果。我相信问题在于我的映射。我查看了这个查询：

  ... localhost：3000 / search / results？utf8 =％E2％9C％ 93& query = product 
  

当我认为应该是：

  ... localhost：3000 / search / results？utf8 =％E2％9C％93& query：product = product 
  

根据此问题： ElasticSearch映射不起作用

我不知道如何使我的 params [：query] 只能使用 product.name 。我试图使用： string params [：query]，default_field：product.name但是没有工作。

我不想使用 _all 字段。

这是我的代码： p>

Price.rb

 包括轮胎： ：模型::搜索
包括轮胎::模型::回调
 
 def self.search（params）
 tire.search（load：true，page：params [：page ]，per_page：20）do 
 query do 
 boolean do 
 must {string params [：query]}如果params [：query] .present？ 
 must {term：private，false} 
 end 
 end 
 sort do 
 by：date，desc
由：amount，asc 
 end 
 end 
 end 
 
 def to_indexed_json 
 to_json（include：{product：{only：[：name]}}）
 end 
 
 mapping do 
索引：id，类型：integer
索引：金额，类型：string，索引：not_analyzed
索引：日期，键入：date，index：not_analyzed
索引：private，type：boolean
索引：product do 
索引：名称，类型：string custom_analyzer
 end 
 end 
 
设置分析：{
 analyzer：{
 custom_analyzer：{
 tokenizer：[whitespace，小写]，
过滤器：[ngram_filter，word_delimiter_filter]，
类型：自定义
} 
}，
过滤器：{
 ngram_filter：{
 typ e：nGram，
 min_gram：2，
 max_gram：15 
} 
}，
过滤器：{
 word_delimiter_filter：{
键入：word_delimiter，
 generate_word_parts：true，
 generate_number_parts：true，
 preserve_original：true，
 stem_english_possessive：true 
} 
} 
} 
  

任何人都有任何建议或知道如何设置查询字段以使用产品名称只有？

谢谢。

解决方案

令人头疼，所以我结束了 Ransack ，这个比较容易弄清楚和使用。 p>

I'm using Tire for Elastic Search. In my application I have 2 models; Price and Product.

I'm trying to search my Price class and use the Product it belongs to's :name attribute for the search field. Right now if I had a product called Product 1 and type in "pro", "prod" or "duct", no results come up. But typing "product" or "Product" shows the results. I believe the problem lies in my mapping. I looked at the query and its:

...localhost:3000/search/results?utf8=%E2%9C%93&query=product

When I think it should be:

...localhost:3000/search/results?utf8=%E2%9C%93&query:product=product

Judging by this question: ElasticSearch mapping doesn't work

I don't know how to make my params[:query] to take the product.name only though. I tried to use: string params[:query], default_field: "product.name" but that didn't work.

I don't want to use the _all field.

Here is my code:

Price.rb

  include Tire::Model::Search
  include Tire::Model::Callbacks

  def self.search(params)
    tire.search(load: true, page: params[:page], per_page: 20) do
       query do
         boolean do
            must { string params[:query] } if params[:query].present?
            must { term :private, false }
         end
       end
       sort do
         by :date, "desc"
         by :amount, "asc"
       end
    end
  end

  def to_indexed_json
    to_json( include: { product: { only: [:name] } } )
  end

  mapping do
    indexes :id,        type: "integer"
    indexes :amount,    type: "string", index: "not_analyzed"
    indexes :date,      type: "date",   index: "not_analyzed"
    indexes :private,   type: "boolean"
    indexes :product do
      indexes :name, type: "string", analyzer: "custom_analyzer"
    end
  end

  settings analysis: {
    analyzer: {
      custom_analyzer: {
        tokenizer: [ "whitespace", "lowercase" ],
        filter: [ "ngram_filter", "word_delimiter_filter" ],
        type: "custom"
      }
    },
    filter: {
      ngram_filter: {
        type: "nGram",
        min_gram: 2,
        max_gram: 15
      }
    },
    filter: {
      word_delimiter_filter: {
        type: "word_delimiter",
        generate_word_parts: true,
        generate_number_parts: true,
        preserve_original: true,
        stem_english_possessive: true
      }
    }
  }

So does anyone have any suggestions or know how to set the query field to use the Product name only?

Thank you.

解决方案

This was to much of a headache so I ended going to Ransack which was insanely much easier to figure out and use.

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