弹性搜索：得分为百分比 [英] Elastic Search: score as percentage

问题描述

是否有可能对弹性搜索进行查询，以最高分数的百分比返回分数？到目前为止，它返回一个值，例如_ score：0.00786336，，最大分数如 max_score：0.13435546 所以我可以尝试转换我的结果，但我希望结果已经达到百分比，所以我可以使用最低分，例如40％。

$ b简而言之：有没有办法以最高分数的百分比获得_score，还是设置最小分数的另一种方法？（似乎很难，因为max_score似乎是随机的）

解决方案

一种方法是存储查询散列和min_score（以最大分数计算），例如，如果max_score是1.1，该查询的min_score可以为0.44，这有助于切断不相关的结果。

Is it possible to make a query for Elastic Search that returns a score as a percentage of the maximum score? Until now it returns a value like "_score": 0.00786336, and also a maximum score like max_score": 0.13435546, so I could try to convert my result but I want the result to be already in percentages, so I could use a minimum score, for example of 40 percent.

In short: Is there a way to get the _score in percentages of the max score, or is there another way of setting a minimum score? (seems to be hard because the max_score seems random)

解决方案

One way to do it can be to store the query hashes and the min_score (calculated as a percentage of max score). For example if the max_score is 1.1 the min_score can be 0.44 for that query which can help cut off irrelevant results.

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