在ElasticSearch中的matchAllQuery（） [英] matchAllQuery() in ElasticSearch

问题描述

Elasticsearch中的matchAllQuery（）只能获得10个结果，如何增加其输出，以便根据我的要求获得尽可能多的结果。

代码

  QueryBuilder query = QueryBuilders.matchAllQuery（）; 
  

解决方案

是的，你可以做， c $ c> aPageRequestcount 无论你想要什么，如果你希望弹性搜索中没有记录存在于 repository.count（）将适用于： -

  int aPageRequestcount =（int）repository.count（）; 
 
 NativeSearchQueryBuilder aNativeSearchQueryBuilder = new NativeSearchQueryBuilder（）; 
 aNativeSearchQueryBuilder.withIndices（indexName）.withTypes（type）.withPageable（new PageRequest（0，aPageRequestcount））; 
 final BoolQueryBuilder aQuery = new BoolQueryBuilder（）; 
 
 
 NativeSearchQuery nativeSearchQuery = aNativeSearchQueryBuilder.withQuery（aQuery）.build（）; 
 = elasticsearchTemplate.queryForList（nativeSearchQuery，A.class）; 
  

matchAllQuery() in Elasticsearch gets me only 10 results how do I increase its output so that I can get as many results as per my requirement.

Code

 QueryBuilder query = QueryBuilders.matchAllQuery();

解决方案

Yes u can do , here you can pass aPageRequestcount whatever you want and If you want no of records exist in Elastic search than repository.count() will work for that :-

int aPageRequestcount = (int) repository.count();

NativeSearchQueryBuilder aNativeSearchQueryBuilder = new NativeSearchQueryBuilder();  
      aNativeSearchQueryBuilder.withIndices(indexName).withTypes(type).withPageable(new PageRequest(0, aPageRequestcount));
final BoolQueryBuilder aQuery = new BoolQueryBuilder();


NativeSearchQuery nativeSearchQuery = aNativeSearchQueryBuilder.withQuery(aQuery).build();
                = elasticsearchTemplate.queryForList(nativeSearchQuery, A.class);

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