Laravel许多加载相关型号与数量 [英] Laravel many to many loading related models with count

问题描述

我试图链接4个表，并添加一个通过使用laravel计数一些相关表的id来计算的自定义字段。
我有这个在SQL中做我想要的，但我认为它可以更有效率：

I am trying to link 4 tables and also add a custom field calculated by counting the ids of some related tables using laravel. I have this in SQL which does what I want, but I think it can be made more efficient:

DB::select('SELECT 
                        posts.*,
                          users.id AS users_id, users.email,users.username,
                          GROUP_CONCAT(tags.tag ORDER BY posts_tags.id) AS tags,
                          COUNT(DISTINCT comments.id) AS NumComments, 
                          COUNT(DISTINCT vote.id) AS NumVotes
                        FROM 
                          posts    
                          LEFT JOIN comments ON comments.posts_id = posts.id
                          LEFT JOIN users ON users.id = posts.author_id
                          LEFT JOIN vote  ON vote.posts_id = posts.id
                          LEFT JOIN posts_tags  ON posts_tags.posts_id = posts.id
                          LEFT JOIN tags  ON tags.id = posts_tags.tags_id

                        GROUP BY 
                          posts.id, 
                          posts.post_title');

我试图通过这样做通过雄辩实现：

I tried to implement it using eloquent by doing this:

$trending=Posts::with(array('comments' => function($query)
                {
                    $query->select(DB::raw('COUNT(DISTINCT comments.id) AS NumComments'));

                },'user','vote','tags'))->get();

但是，查询结果中没有显示NumComments值。
任何线索还有什么可以吗？

However the NumComments value is not showing up in the query results. Any clue how else to go about it?

推荐答案

你不能使用 / code>，因为它执行单独的查询。

You can't do that using with, because it executes separate query.

你需要的是简单的 join 。只需翻译您所需的查询：

What you need is simple join. Just translate the query you have to something like:

Posts::join('comments as c', 'posts.id', '=', 'c.id')
    ->selectRaw('posts.*, count(distinct c.id) as numComments')
    ->groupBy('posts.id', 'posts.post_title')
    ->with('user', 'vote', 'tags')
    ->get();

那么收藏中的每个帖子都会有count属性：

then each post in the collection will have count attribute:

$post->numComments;

---

然而，您可以使以下关系更容易：

尽管第一个解决方案在性能方面更好（可能不明显，除非您有大数据）

---

However you can make it easier with relations like below:

Though first solution is better in terms of performance (might not be noticeable unless you have big data)

// helper relation
public function commentsCount()
{
    return $this->hasOne('Comment')->selectRaw('posts_id, count(*) as aggregate')->groupBy('posts_id');
}

// accessor for convenience
public function getCommentsCountAttribute()
{
    // if relation not loaded already, let's load it now
    if ( ! array_key_exists('commentsCount', $this->relations)) $this->load('commentsCount');

    return $this->getRelation('commentsCount')->aggregate;
}

这将允许您这样做：

$posts = Posts::with('commentsCount', 'tags', ....)->get();
// then each post:
$post->commentsCount;

对于许多关系：

public function tagsCount()
{
    return $this->belongsToMany('Tag')->selectRaw('count(tags.id) as aggregate')->groupBy('pivot_posts_id');
}

public function getTagsCountAttribute()
{
    if ( ! array_key_exists('tagsCount', $this->relations)) $this->load('tagsCount');

    $related = $this->getRelation('tagsCount')->first();

    return ($related) ? $related->aggregate : 0;
}

更多的例子可以在这里找到 http://softonsofa.com/tweaking-eloquent-relations-how-to- get-hasmany-relation-count-efficient /

More examples like this can be found here http://softonsofa.com/tweaking-eloquent-relations-how-to-get-hasmany-relation-count-efficiently/

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