雄辩的MYSQL语句：WHERE NOT（A或B） [英] Eloquent MYSQL statement : WHERE NOT(A OR B)

问题描述

我正在处理日期范围重叠功能，可以在13个正面条件下编写，以检查日期间隔是否重叠：

I`m working on date-range-overlap functionality that can be written in 13 positive conditions to check if the date intervals overlap :

https://en.wikipedia.org/wiki/Allen%27s_interval_algebra

或更优雅的2个负面条件：

Or more elegantly in 2 negative conditions:

http://baodad.blogspot.nl/2014/06/date-range-overlap.html

在MYSQL中：

WHERE NOT(`last_day` <= '2001-06-01' OR `first_day` >= '2022-12-01');

这将需要这样的东西，我可以在文档中找到：

This would require something like this, which I can`t find in the docs:

$query = $query->whereNot(function ($query) use ($first_day, $last_day) {
   $query->where('last_day', '<=', $first_day);
   $query->orWhere('first_day', '<=', $last_day);
});

我该如何解决？

这与我其他可能重复的帖子有关： Laravel / Enloft在哪里不附加

This is related to my other possibly duplicate post : Laravel / Eloquent WHERE NOT SUBQUERY

但我希望我的问题现在更清楚。

But I hope my question is more clear now.

推荐答案

通过恢复 last_day 和 first_day 之间的约束来实现所需要的 - 这样就不需要使用 NOT 子句。

You can achieve what you need by reverting the constraints on last_day and first_day - this way there is no need to use NOT clause.

而不是

WHERE NOT(`last_day` <= '2001-06-01' OR `first_day` >= '2022-12-01');

你可以做

WHERE `last_day` > '2001-06-01' AND `first_day` < '2022-12-01';

与雄辩的构建者，以下应该做的诀窍：

And with Eloquent builder the following should do the trick:

$query = $query->where('last_day', '>', $first_day)->where('first_day', '>', $last_day);

这篇关于雄辩的MYSQL语句：WHERE NOT（A或B）的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！