过滤雄辩收藏 [英] Filtering Eloquent Collection

问题描述

尝试根据多个值的任意组合向下过滤集合对象。这是我所知道的。没有发生。任何线索给我？

Trying to filter a collection object down based upon any combination of multiple values. This is as far as I've got. Not happening. Any clues for me?

public function search()
{
    $posts = Posting::all();

    $type_id = Input::get('type_id');
    $country_id = Input::get('country_id');
    $province_id = Input::get('province_id');

    $posts = $posts->filter(function($post)
    {
      if( !empty($type_id) && $type_id>0 )
      {
        return $post->where('type_id','=',$type_id);
     }
    })->values();

    $posts = $posts->filter(function($post)
    {
      if( !empty($country_id) && $country_id>0 )
      {
        return $post->where('country_id','=',$country_id);
      }
    })->values();

    $posts = $posts->filter(function($post)
    {
      if( !empty($province_id) && $province_id>0 )
      {
        return $post->where('province_id','=',$province_id);
      }
   })->values();

   return $posts;
}

任何帮助赞赏。

推荐答案

首先，您需要从您的过滤器中的关闭返回有意义的内容：

First off, you need to return something that makes sense from the closure in your filter:

$posts = $posts->filter(function($post)
{
  if( !empty($type_id) && $type_id>0 )
  {
    return $post->where('type_id','=',$type_id);
  }
})

上面返回 Eloquent\Builder 对象，其中被评估为 true ，所以..真的没有意义。

Above returns Eloquent\Builder object, which is evaluated to true, so.. it really doesn't make sense.

这是什么您需要：

$posts = $posts->filter(function($post)
{
  if( !empty($type_id) && $type_id>0 )
  {
    return $post->type_id == $type_id; // bool
  }
})

使用这样的代码，您将过滤该集合。 $ posts 现在将只保留与该关闭中的语句相匹配的项目。

With such code, you will filter the collection. $posts now will hold only those items, that match the statement in that closure.

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