Emacs中的Python Interpreter重复行 [英] Python Interpreter in Emacs repeats lines

问题描述

发生了什么：

 >>> 2 * 10 
 2 * 10 
 20 
>>> 
  

我想要发生什么：

 >>> 2 * 10 
 20 
>>>有没有人知道为什么命令在执行之前打印出来，以及如何阻止它的执行？我找不到任何有关这方面的文件。我在Mac OS X上使用Emacs 23与Python 2.7。 
解决方案
我不使用python，但我猜猜你使用的python功能已经设置了变量 comint-process-echoes 不正确。无论缓冲区中的值如何，只需反转布尔值。
 
 
 
 Comint是Emacs中用于在Emacs中运行较差进程的支持库。它与提示进行交互，需要告知python shell（或Mx shell）的回声功能。
 
 
 
在您的shell缓冲区中，请执行以下操作： / p> 
 
 
  M-：（setq comint-process-echoes t）;;或nil 
  
 
What is happening:
>>> 2 * 10
2 * 10
20
>>> 
What I want to happen:
>>> 2 * 10
20
>>> 
Does anyone know why the command is printed out before being executed and how to stop it from doing that? I can't find any documentation about this. I'm using Emacs 23 on Mac OS X with Python 2.7. 
解决方案
I don't use python, but I would guess that the python feature you are using has set the variable comint-process-echoes incorrectly.  Whatever the value in your buffer is, just reverse the boolean value.

Comint is a support library in Emacs for running inferior processes in Emacs.  It interacts with the prompts, and the python shell (or M-x shell) needs to be told about the echo feature.

In your shell buffer with the problem, do:
M-: (setq comint-process-echoes t)  ;; or nil


                        
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