从CONTACT EMAIL检索CONTACT NAME时获取空值 [英] Getting null value while retrieving the CONTACT NAME from CONTACT EMAIL
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问题描述
我想从联系人电子邮件中检索联系人姓名，所以我从 https：// stackoverflow。 com / a / 18064869/5738881 。
I want to retrieve the contact name from the contact email, so what I have done is as follows from https://stackoverflow.com/a/18064869/5738881.
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
if (cursor == null) {
return null;
}
String contactName = null;
if (cursor.moveToFirst()) {
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "\n" + contactName);
return contactName;
}
然后在onCreate（）中，我编码为，
Then in onCreate(), I have coded as,
sName = readContacts(getApplicationContext(), sEmail);
etName.setText(sName);
但是我得到空值。因此，根据联系人电子邮件地址，取得联系人姓名可能会是什么？
But I am getting the null value. Therefore what could be the soution to fetch contact name, depending upon just the contact email address?
EDIT-1：
EDIT-1:
我已经在清单中提到了许可，
I have already mentioned the permission in manifest as,
<uses-permission android:name="android.permission.READ_CONTACTS"/>
EDIT-2：
EDIT-2:
根据 ROHIT SHARMA 的回答，我更改了我的代码如下。
As per ROHIT SHARMA's answer, I changed my code as below.
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
if (cursor == null) {
return null;
}
String contactName = null;
if (cursor.getCount() > 0) {
cursor.moveToFirst();
} else {
return null;
}
if (cursor.moveToFirst()) {
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "\n" + contactName);
return contactName;
}
但这并没有帮助我。 p>
But it didn't help me as well.
EDIT-3：
EDIT-3:
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
String contactName = null;
if(cursor!=null && cursor.getCount()>0 )
{
cursor.moveToFirst();
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}else{
return null;
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "\n" + contactName);
return contactName;
}
它没有帮助我。 >
It didn't help me as well.
EDIT-4：
EDIT-4:
p>
I tried
public String readContacts(Context context, String email) {
String name = null;
// define the columns I want the query to return
String[] projection = new String[]{
ContactsContract.PhoneLookup.DISPLAY_NAME,
ContactsContract.PhoneLookup._ID};
// encode the email and build the filter URI
Uri contactUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
// query time
Cursor cursor = context.getContentResolver().query(contactUri, projection, null, null, null);
if (cursor != null) {
if (cursor.moveToFirst()) {
name = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
Log.e("....email.....", "Started uploadcontactphoto: Contact Found @ " + email);
Log.e("....name....", "Started uploadcontactphoto: Contact name = " + name);
} else {
Log.e("....email exception....", "Contact Not Found @ " + email);
}
cursor.close();
}
return name;
}
from https://stackoverflow.com/a/15007980/5738881 ，但没有帮助。
from https://stackoverflow.com/a/15007980/5738881 but didn't help as well.
任何人还有其他出路？
编辑5：
EDIT-5:
public String readContacts() {
ContentResolver cr = getContentResolver();
@SuppressLint("Recycle")
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
null, null, null, null);
String id, name = null, email = null;
if (cur != null && cur.getCount() > 0) {
while (cur.moveToNext()) {
id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
System.out.println("name : " + name + ", ID : " + id);
// get the phone number
Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id}, null);
if (pCur != null) {
while (pCur.moveToNext()) {
String phone = pCur.getString(
pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
System.out.println("phone" + phone);
}
}
if (pCur != null) {
pCur.close();
}
// get email and type
Cursor emailCur = cr.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",
new String[]{id}, null);
if (emailCur != null) {
while (emailCur.moveToNext()) {
// This would allow you get several email addresses
// if the email addresses were stored in an array
email = emailCur.getString(
emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
String emailType = emailCur.getString(
emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.TYPE));
System.out.println("Email " + email + " Email Type : " + emailType);
}
if (email == sEmail) {
sName = name;
}
}
if (emailCur != null) {
emailCur.close();
}
}
}
}
return name;
}
我尝试过从 http://www.coderzheaven.com/2011/06/13/get -all-details-from-contacts-in-android / ，我正在获得名称，但它的名称与电子邮件ID所有者不同。
I tried above code instance from http://www.coderzheaven.com/2011/06/13/get-all-details-from-contacts-in-android/ and I am getting name, but it is different name than the email id owner.
所以，告诉我我在哪里出错..
So, tell me where I am going wrong..
从上面的代码片段，我也尝试过
And from above code snippet, I have also tried
if (email == sEmail) {
sName = name;
}
System.out.println("Email " + email + " Email Type : " + emailType);
}
}
if (emailCur != null) {
emailCur.close();
}
而不是
System.out.println("Email " + email + " Email Type : " + emailType);
}
if (email == sEmail) {
sName = name;
}
}
if (emailCur != null) {
emailCur.close();
}
但没有帮助。
推荐答案
您应该替换
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
与
Uri uri = Uri.withAppendedPath(ContactsContract.CommonDataKinds.Email.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.CommonDataKinds.Email.CONTACT_ID,
ContactsContract.Data.DISPLAY_NAME}, null, null, null);
然后测试..
这篇关于从CONTACT EMAIL检索CONTACT NAME时获取空值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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