如何用python来安全地编码一个字符串？和urllib.quote是错误的 [英] how to url-safe encode a string with python? and urllib.quote is wrong

问题描述

你好，我想知道你是否知道任何其他方法来编码字符串到一个url-safe，因为urllib.quote是错误的，输出是不同于预期的：

Hello i was wondering if you know any other way to encode a string to a url-safe, because urllib.quote is doing it wrong, the output is different than expected:

如果我尝试

urllib.quote（'á' ）

urllib.quote('á')

我得到

'％C3％A1'

但是这不是正确的输出，它应该是
％E1

But thats not the correct output, it should be %E1

由本网站

这不是我很难，引用的错误输出阻止浏览器找到资源，如果我尝试

And this is not me being difficult, the incorrect output of quote is preventing the browser to found resources, if i try

urllib.quote（'\images\á\somefile.jpg'）

urllib.quote('\images\á\some file.jpg')

然后我尝试使用javascript工具，我提到我分别得到这个字符串

And then i try with the javascript tool i mentioned i get this strings respectively

％5Cimages％5C％C3％A1％ 5Csome％20file.jpg

%5Cimages%5C%C3%A1%5Csome%20file.jpg

％5Cimages％5C％E1％5Csome％20file.jpg

%5Cimages%5C%E1%5Csome%20file.jpg

注意如何几乎相同，但由引用提供的url不起作用，另一个则是这样。
我尝试在提供给引用的字符串上编码（'utf-8），但是没有什么区别。
我用其他西班牙语的单词用口音尝试，ñ他们都有不同的表示。

Note how is almost the same but the url provided by quote doesn't work and the other one it does. I tried messing with encode('utf-8) on the string provided to quote but it does not make a difference. I tried with other spanish words with accents and the ñ they all are differently represented.

这是一个python bug吗？
你知道某个模块是否正确？

Is this a python bug? Do you know some module that get this right?

推荐答案

根据 RFC 3986 ，％C3％A1 是正确的。在字节流被百分比编码之前，字符应该使用UTF-8转换为八位字节流。您链接的网站已过期。

According to RFC 3986, %C3%A1 is correct. Characters are supposed to be converted to an octet stream using UTF-8 before the octet stream is percent-encoded. The site you link is out of date.

请参阅为什么URL的编码和查询字符串部分不同？有关处理非历史记录的更多详细信息-ASCII字符。

See Why does the encoding's of a URL and the query string part differ? for more detail on the history of handling non-ASCII characters in URLs.

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