获取下一个枚举器常量/属性 [英] Get next enumerator constant/property

问题描述

让我们说我有一个枚举器，是否可以获得跟随的属性？所以如果我有 today = Days.Sunday ，我可以做一些类似 tomorrow = today.next（） ？

示例：

  class Days（Enum）：
星期日='S'
星期一='M'
 ... 
星期六='Sa'
  

我知道我可以使用元组（如下所示）来执行类似 tomorrow = today [1] 的内容，但我希望在是内置的或更优雅的东西。

  class Days（枚举）：
星期日=（'S' 
 
 $ / code > 




解决方案

绝对。

只需在天添加所需的功能类：

$（$）code

星期日='S'
星期一='M'
星期二='T'
星期三='W'
星期四='Th'
星期五='F'
星期六='Sa'

def next（self）：
cls = self .__ class__
members = list（cls）
index = members.index（self）+ 1
if index> = len（members）：
index = 0
返回成员[index]

并使用：

  today = Days.Wednesday 
 print（today.next（））
＃Days.Thursday 
  




Lets's say I have an enumerator, is it possible to get the property that follows? So if I had today=Days.Sunday would I be able to do something like tomorrow=today.next()?

example:

class Days(Enum):
     Sunday = 'S'
     Monday = 'M'
     ...
     Saturday = 'Sa'

I know I could use tuples (like below) to do something like tomorrow=today[1], but I was hoping there was something built in or more elegant.

class Days(Enum):
     Sunday = ('S','Monday')
     Monday = ('M','Tuesday')
     ...
     Saturday = ('Sa','Sunday')

解决方案

Absolutely.

Just add the desired functionality to your Days class:

class Days(Enum):

    Sunday = 'S'
    Monday = 'M'
    Tuesday = 'T'
    Wednesday = 'W'
    Thursday = 'Th'
    Friday = 'F'
    Saturday = 'Sa'

    def next(self):
        cls = self.__class__
        members = list(cls)
        index = members.index(self) + 1
        if index >= len(members):
            index = 0
        return members[index]

and is use:

today = Days.Wednesday
print(today.next())
# Days.Thursday

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