枚举中具有多个值的java.lang.ExceptionInInitializerError [英] java.lang.ExceptionInInitializerError in enum with multiple values

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本文介绍了枚举中具有多个值的java.lang.ExceptionInInitializerError的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这是枚举的代码(在单例类中):

This is the code of enum (inside of singleton class):

public class GlobalStore extends Application{
.....
......
.....
public synchronized static GlobalStore getInstance() {
    if(instance==null){
        instance = new GlobalStore();
    }
    return instance;
}

.....
......

public static enum Category {
    CATEGORIA_DB(1,instance.getString(R.string.cat_dep_bel),"db"),
    CATEGORIA_EL(2,instance.getString(R.string.cat_edu_lec),"el"),
    CATEGORIA_E(3,instance.getString(R.string.cat_entre),"e"),
    CATEGORIA_EM(4,instance.getString(R.string.cat_est_mod),"em"),
    CATEGORIA_GV(5,instance.getString(R.string.cat_gas_vinos),"gv"),
    CATEGORIA_DH(6,instance.getString(R.string.cat_dis_hog),"dh"),
    CATEGORIA_S(7,instance.getString(R.string.cat_salud),"s"),
    CATEGORIA_ST(8,instance.getString(R.string.cat_ser_tec),"st"),
    CATEGORIA_T(9,instance.getString(R.string.cat_turis),"t"),
    CATEGORIA_AC(10,instance.getString(R.string.cat_arte_cultura),"ac");


    private final int id;
    private final String gloss;
    private final String code;

    Category(int mId, String mGloss, String mCode) {
        this.id = mId;
        this.gloss = mGloss;
        this.code = mCode;
    }

    public int getId() {
        return id;
    }

    public String getGloss() {
        return gloss;
    }

    public String getImagen() {
        return "icon_"+code;
    }

    public String getSelectedImagen() {
        return this.getImagen() + "_red";
    }

    public String getDrawString() {
        return "mn_"+code+"1";
    }

}

此行中的错误:

public static Category findCategoryById(int mId) {

    for (Category categoria : Category.values()) { //HERE is error in Category.values() -- line 327
        if (categoria.getId()==mId) {
            return categoria;
        }
    }
    return null;
}

.....
}

更新

logcat中的错误:

the error in logcat:

01-24 05:42:49.310 31800-31800/? E/AndroidRuntime: FATAL EXCEPTION: main
01-24 05:42:49.310 31800-31800/? E/AndroidRuntime: Process: com.assertsoft.beneplus.alpha, PID: 31800
01-24 05:42:49.310 31800-31800/? E/AndroidRuntime: java.lang.ExceptionInInitializerError
01-24 05:42:49.310 31800-31800/? E/AndroidRuntime:     at com.assertsoft.model.GlobalStore.findCategoriaById(GlobalStore.java:327)
01-24 05:42:49.310 31800-31800/? E/AndroidRuntime:     at com.assertsoft.adapters.ListaCuponesAdapter.getView(ListaCuponesAdapter.java:196)


推荐答案

我相信你的代码在这里:

I believe your code here:

Category(int mId, String mGloss, String mCode) {
        this.id = mId;
        this.gloss = mGloss;
        this.code = mCode;
    }

期望三个值初始化。但是这行:

expects three values to be initialised. But this line :

public static Category findCategoryById(int mId)

只是其中的一个。在静态上下文中,所有参数都需要初始化。

is initialising just one out of those. In that static context all the parameters needs to be initialised.

这篇关于枚举中具有多个值的java.lang.ExceptionInInitializerError的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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