增加或减少色彩饱和度 [英] Increase or decrease color saturation
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问题描述
我想知道该算法以增加或减少1 RGB色彩饱和度
I would like to know the algorithm to increase or decrease one RGB color saturation
例如,如果我有颜色 RGB(200,30,40)
(红色)的函数存根会
for example if I have the color rgb(200, 30, 40)
(red) the function stub would be
function Saturation(color, factor)
where color.r = 200, color.g= 30 and color.b=40
任何人都知道图书馆或具有code段,做了吗?
Anyone knows a library or has a code snippet that does that?
推荐答案
继巴厘岛巴洛建议,我想出了:
Following Bali Balo suggestion I came up with:
RGBtoHSV= function(color) {
var r,g,b,h,s,v;
r= color[0];
g= color[1];
b= color[2];
min = Math.min( r, g, b );
max = Math.max( r, g, b );
v = max;
delta = max - min;
if( max != 0 )
s = delta / max; // s
else {
// r = g = b = 0 // s = 0, v is undefined
s = 0;
h = -1;
return [h, s, undefined];
}
if( r === max )
h = ( g - b ) / delta; // between yellow & magenta
else if( g === max )
h = 2 + ( b - r ) / delta; // between cyan & yellow
else
h = 4 + ( r - g ) / delta; // between magenta & cyan
h *= 60; // degrees
if( h < 0 )
h += 360;
if ( isNaN(h) )
h = 0;
return [h,s,v];
};
HSVtoRGB= function(color) {
var i;
var h,s,v,r,g,b;
h= color[0];
s= color[1];
v= color[2];
if(s === 0 ) {
// achromatic (grey)
r = g = b = v;
return [r,g,b];
}
h /= 60; // sector 0 to 5
i = Math.floor( h );
f = h - i; // factorial part of h
p = v * ( 1 - s );
q = v * ( 1 - s * f );
t = v * ( 1 - s * ( 1 - f ) );
switch( i ) {
case 0:
r = v;
g = t;
b = p;
break;
case 1:
r = q;
g = v;
b = p;
break;
case 2:
r = p;
g = v;
b = t;
break;
case 3:
r = p;
g = q;
b = v;
break;
case 4:
r = t;
g = p;
b = v;
break;
default: // case 5:
r = v;
g = p;
b = q;
break;
}
return [r,g,b];
}
通过转换到HSV(色调,饱和度和值)的格式,你可以手动更改S成分以这种方式:
by converting to the HSV (hue, saturation and value) format you can manually change the S component in this manner:
var hsv= RGBtoHSV ([200,100,100]);
alert(hsv)
hsv[1] *= 1.5;
alert(hsv)
var rgb= HSVtoRGB(hsv);
alert(rgb); //new color
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