从PHP CLI脚本运行命令之前导出shell环境变量 [英] export shell environment variable before running command from PHP CLI script

问题描述

我有一个脚本，使用 passthru（）来运行命令。我需要在运行此命令之前设置一些shell环境变量，否则将无法找到它的库。

我尝试过以下操作：

  putenv（LD_LIBRARY_PATH = / path / to / lib）; 
 passthru（$ cmd）; 
  

使用 putenv（）似乎不传播到我正在运行的命令。它不能说它找不到它的库。当我在bash中运行 export LD_LIBRARY_PATH = / path / to / lib 时，可以正常运行。

以下（无效）：

  exec（export LD_LIBRARY_PATH = / path / to / lib）; 
 passthru（$ cmd）; 
  

如何从PHP设置一个shell变量，传播到PHP脚本的子进程？ / p>

我只限于检查当前环境中是否不存在变量，并要求用户手动设置？

解决方案

我不是很熟悉PHP的exec如何工作，但是你尝试过： exec（LD_LIBRARY_PATH = / path / to / lib $ cmd ）

我知道这在大多数shell中都有效，但我不知道PHP在做什么。

编辑：假设这是正常的，要处理多个变量，只需将它们分开一个空格：

exec VAR1 = val1 VAR2 = val2 LD_LIBRARY_PATH = / path / to / lib $ cmd）

I have a script that uses passthru() to run a command. I need to set some shell environment variables before running this command, otherwise it will fail to find it's libraries.

I've tried the following:

putenv("LD_LIBRARY_PATH=/path/to/lib");
passthru($cmd);

Using putenv() doesn't appear to propagate to the command I'm running. It fails saying it can't find it libraries. When I run export LD_LIBRARY_PATH=/path/to/lib in bash, it works fine.

I also tried the following (in vain):

exec("export LD_LIBRARY_PATH=/path/to/lib");
passthru($cmd);

How can I set a shell variable from PHP, that propagates to child processes of my PHP script?

Am I limited to checking if a variable does not exist in the current environment and asking the user to manually set it?

解决方案

I'm not 100% familiar with how PHP's exec works, but have you tried: exec("LD_LIBRARY_PATH=/path/to/lib $cmd")

I know that this works in most shells but I'm not sure how PHP doing things.

EDIT: Assuming this is working, to deal with multiple variables just separate them by a space:

exec("VAR1=val1 VAR2=val2 LD_LIBRARY_PATH=/path/to/lib $cmd")

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