如何实现前进和后退功能，例如浏览器 [英] how to implement back and forward functionality like browser

问题描述

我想实现像回到了功能和前锋在我的项目相同的浏览器，如网页我们在屏幕上。 我试过是 intially中号设置 currentscreenindex = -1

I want to implement functionality like back and forward in my project same as browser , like web page we have the screen. what i tried is intially m setting the currentscreenindex=-1

和在第一屏的数据来执行此功能

and when data of first screen comes execute this function

In screen data arrive function (){
   this.currentscreenindex++; 
   this.screenvisited[this.currentscreenindex]=data;

}

下面是我的背部功能是我的尝试：

Here is my back function what i tried :

back(){
    currentscreenindex--;
    var screen=screenvisited[currentscreenindex];
    // will go to this screen
}

但我的问题是这些是：

but what my problem is in these is :

                    currentscreenindex  screen data in screenvisted array
When 1st screen arrived     0     Data of 1st screen 
When 2st screen arrived     1     Data of 2st screen 
When 3st screen arrived     2     Data of 3st screen 
When 4st screen arrived     3     Data of 4st screen 
When 5st screen arrived     4     Data of 5st screen 
when user click back button 3     call the screen is set to 4th gib, 

因此​​，当第四屏数据到货，目前指数将得到增量， CURRENTINDEX = 4 和数据在当前索引4将成为第四屏的，我认为这是不正确的，因为如果在 CURRENTINDEX = 4 数据将得到改变，那么我不能这样做前锋，如果是的话请告诉我如何纠正呢？

so when data of 4th screen arrive , the current index will get incremented so currentindex=4 and data at current index 4 will be of 4th screen , i think it is not correct , because if data at currentindex=4 will get changed then i can't do forward , if yes pls tell how can i correct it ?

请建议我怎么能写正确的前进和后退的功能做相同的功能的浏览器。

please suggest how can i write the proper back and forward function to do same functionality as browser .

推荐答案

我不知道你如何适应这个到你如何目前正在做，但你可以实现这样的功能：

I don't know how you'd fit this into how you're currently doing it, but you can achieve the functionality like this:

您有两个堆栈。背堆栈和一个堆栈。他们都开始了为空。当用户通过链接或航行的其他方法，除了后退/前进导航到一个新的页面，清除了下一个堆栈，当前网页添加到后退堆栈，并继续航行。当用户点击后面，将当前页面上的正向堆栈，从后面栈中弹出一个页面，并导航到弹出页面。当用户点击向前，将当前页面上的后退堆栈，从正向栈中弹出一个页面，并导航到弹出页面。

You have two stacks. A back stack and a next stack. They both start out being empty. When the user navigates to a new page through a link or some other method of navigation besides back/forward, clear the next stack, add the current page to the back stack, and continue navigation. When the user clicks back, push the current page onto the forward stack, pop a page from the back stack, and navigate to the popped page. When the user clicks forward, push the current page onto the back stack, pop a page from the forward stack, and navigate to the popped page.

编辑：：您问一些伪code，所以在这里你走：

You asked for some pseudocode, so here you go:

var currentPage=null;
var backStack=[];
var forwardStack=[];
function navigate(newPage) {
    currentPage=newPage;
    // stub
}
function linkClicked(page) {
    backStack.push(currentPage);
    forwardStack=[];
    navigate(page);
}
function goBack() {
    forwardStack.push(currentPage);
    navigate(backStack.pop());
}
function goForward() {
    backStack.push(currentPage);
    navigate(forwardStack.pop());
}

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