我如何在erlang中分割一个二进制文件 [英] How can i split a binary in erlang

问题描述

我想要的是比较简单：

> Bin = <<"Hello.world.howdy?">>.
> split(Bin, ".").
[<<"Hello">>, <<"world">>, <<"howdy?">>]

任何指针？

推荐答案

没有当前的OTP功能，相当于列表：split / 2 ，它适用于二进制字符串。直到 EEP-9 被公开，你可能会写一个二进制拆分功能，如：

There is no current OTP function that is the equivalent of lists:split/2 that works on a binary string. Until EEP-9 is made public, you might write a binary split function like:

split(Binary, Chars) ->
    split(Binary, Chars, 0, 0, []).

split(Bin, Chars, Idx, LastSplit, Acc)
  when is_integer(Idx), is_integer(LastSplit) ->
    Len = (Idx - LastSplit),
    case Bin of
        <<_:LastSplit/binary,
         This:Len/binary,
         Char,
         _/binary>> ->
            case lists:member(Char, Chars) of
                false ->
                    split(Bin, Chars, Idx+1, LastSplit, Acc);
                true ->
                    split(Bin, Chars, Idx+1, Idx+1, [This | Acc])
            end;
        <<_:LastSplit/binary,
         This:Len/binary>> ->
            lists:reverse([This | Acc]);
        _ ->
            lists:reverse(Acc)
    end.

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