Swift类不符合具有错误处理的Objective-C协议 [英] Swift class does not conform to Objective-C protocol with error handling

问题描述

我有 Objective-C 协议

@protocol SomeObjCProtocol
- (BOOL) doSomethingWithError: (NSError **)error;
@end

And Swift class

And Swift class

class SwiftClass : SomeObjCProtocol
{
    func doSomething() throws {    
    }
}

编译器给我一个错误

键入'SwiftClass'不符合协议'SomeObjCProtocol'

Type 'SwiftClass' does not conform to protocol 'SomeObjCProtocol'"

有没有解决方案如何摆脱这个错误？
我正在使用 XCode 7 Beta 4

Is there any solution how to get rid of this error? I'm using XCode 7 Beta 4

推荐答案

有两个问题：

• Swift 2映射 func doSomething（）throws 到Objective-C方法
  - （BOOL）doSomethingAndReturnError：（NSError **）error; code>，这是
不同于您的协议方法。


• 协议方法必须标记为Objective-C兼容与 @objc 属性。

• Swift 2 maps func doSomething() throws to the Objective-C method - (BOOL) doSomethingAndReturnError: (NSError **)error;, which is different from your protocol method.
• The protocol method must be marked as "Objective-C compatible" with the @objc attribute.

有两种可能解决方案：

解决方案1：将Objective-C协议方法重命名为

Solution 1: Rename the Objective-C protocol method to

@protocol SomeObjCProtocol
- (BOOL) doSomethingAndReturnError: (NSError **)error;
@end

解决方案2：
离开Objective-C协议方法，并且明确指定Swift方法
的Objective-C映射：

Solution 2: Leave the Objective-C protocol method as it is, and specify the Objective-C mapping for the Swift method explicitly:

@objc(doSomethingWithError:) func doSomething() throws {
    // Do stuff
}

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