如何一致地处理球衣和tomcat错误？ [英] How to handle jersey and tomcat errors consistently?

问题描述

我已经用运动衫实现了一些（REST）服务。如果有一个不好的请求，针织衫处理错误并回答一些JSON内容。有一个ExceptionMapper应该捕获一切：

I have implemented some (REST) service with jersey. If there is a bad request jersey handles the error and answers with some JSON content. There is an ExceptionMapper that should catch everything:

public class MyExceptionMapper implements ExceptionMapper<Throwable>

但是如果HTTP请求无效 - 例如无效内容类型 - tomcat处理异常之前，泽西有机会这样做。所得到的响应是一些丑恶的tomcat HTML错误页面而不是所需的JSON。

But if there is an invalid HTTP request - e.g. invalid content type - tomcat handles the exception before jersey has a chance to do so. The resulting response is some ugly tomcat HTML error page instead of the desired JSON.

我知道可以设置一个< error-页面> 在部署描述符中，但是我无法访问任何错误详细信息。

I know that it is possible to set an <error-page> in the deployment descriptor but there I have no access to any error details.

有没有办法防止tomcat捕获此错误？如果是这样，球衣可以用它的ExceptionMapper抓住它并返回正确的响应。

Is there a way to prevent tomcat from catching this error? If so, jersey could catch it with its ExceptionMapper and return the correct response.

推荐答案

你知道你可以设置一个错误页面但是你指向什么？如果它只是一个静态网页，那么是的，您将无法访问错误详细信息。但是如果将它转发到一个用于处理错误的servlet，那么你应该有关于你的错误的详细信息，并且可以将控制权传回给球衣等。

You know you can set an "error page", but what are you pointing it to? If it's just a static webpage, then yes, you won't have access to error details. But if you forward it to a servlet that is made for handling errors, then you should have details on your your error, and can pass control back to jersey, etc.

即

web.xml：

  <error-page>
    <error-code>415</error-code>
    <location>/InvalidContentHandler</location>
  </error-page>
  <error-page>
    <exception-type>java.lang.Throwable</exception-type>
    <location>/InvalidContentHandler</location>
  </error-page>

注意：在上述web.xml中，应该替换java。 lang.Throwable与您遇到的实际异常类型，您可以使用javax.servlet.error.exception属性获取，如下所示。

NOTE: in the above web.xml, you should replace java.lang.Throwable with the actual exception type you are encountering, which you can get with the "javax.servlet.error.exception" attribute, shown below.

InvalidContentHandler.java：

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    processError(request, response);
}

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    processError(request, response);
}

private void processError(HttpServletRequest request, HttpServletResponse response) throws IOException {

    // Pass control to Jersey, or get some info:
    Throwable throwable = (Throwable) request.getAttribute("javax.servlet.error.exception");
    Integer statusCode = (Integer) request.getAttribute("javax.servlet.error.status_code");
    String servletName = (String) request.getAttribute("javax.servlet.error.servlet_name");
    String requestUri = (String) request.getAttribute("javax.servlet.error.request_uri");
    ...
}

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