如何在Bash / Grep中避免单引号？ [英] How to escape single quotes in Bash/Grep?

问题描述

我想使用grep搜索一个如下所示的字符串：

  something〜*'bla'
  

我尝试过这个，但是shell删除了单引号argh ..

  grep -i'something〜*'[：alnum：]''/ var / log / syslog 
  pre> 
 
 
什么是正确的搜索？
解决方案
 
  grep -isomething〜\ *'[[：alnum：]] *'/ var / log / syslog 
  
适用于我。
 
 
 
 
 
转义第一个 * 匹配文字 * ，而不是使其成为零或多匹配字符：
 
  〜* 将匹配零个或多个出现的〜而
 
 〜\ * 与之后的表达式〜* 匹配 
 
 
使用在之间的双括号：alnum：（参见示例 here ）
 
 
使用 *  after  [[：alnum ::]] 不仅可以匹配单引号之间的一个字符，还有几个
 
 
单引号不需要转义，因为它们包含在受双引号限制的表达式中。
 
 
 
I want to search with grep for a string that looks like this:
something ~* 'bla'
I tried this, but the shell removes the single quotes argh..
grep -i '"something ~* '[:alnum:]'"' /var/log/syslog
What would be the correct search?
解决方案
grep -i "something ~\* '[[:alnum:]]*'" /var/log/syslog
works for me.


escape the first * to match a literal * instead of making it the zero-or-more-matches character:

~* would match zero or more occurrences of ~ while

~\* matches the expression ~* after something
use double brackets around :alnum: (see example here)
use a * after [[:alnum::]] to match not only one character between your single quotes but several of them 
the single quotes don't have to be escaped at all because they are contained in an expression that is limited by double quotes.


                        
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