找到以破折号开头的目录 [英] find in directory that starts with dash

问题描述

find 将文件名开头的破折号解释为选项的开头。使用熟悉的 - 技巧不起作用，因为选项在文件名后，引用没有任何效果，并用 \-替换第一个虚线， 也无效。经常鼓励用户使用 ./ 之前的这些文件名，但如果不知道给定的路径是绝对还是相对的，我该怎么办？

find interprets a dash at the start of a filename as the start of an option. Using the familiar -- trick doesn't work since options are after the filename, quoting has no effect, and replacing the first dash with \- doesn't work either. Users are often encouraged to precede such filenames with ./, but what can I do if I don't know whether the given path will be absolute or relative?

编辑：一个解决方案是 find$（readlink -f - $ test_filename），但它是丑陋的。任何更好的想法？

One solution is to find "$(readlink -f -- "$test_filename")", but it's ugly. Any better ideas?

编辑2 ：感谢您的建议。以下是这项工作产生的两个脚本： safe-find.sh ; safe-count-files.sh

Edit 2: Thanks for the suggestions. Here are the two scripts that resulted from this effort: safe-find.sh; safe-count-files.sh

推荐答案

这可能看起来有点便宜，但实际上我推荐你已经想出的 readlink 解决方法。根据 Unix标准，

This may seem a bit cheap, but I actually recommend the readlink workaround that you've figured out. According to the Unix standard,

以
' - '（...）开头的所有后续参数
的第一个参数将被解释为
表达式

所以 - 。 thkala的解决方案也可以正常工作，但是我发现它的可读性差。可能会更快，但如果您正在做很多查找调用。

so -- will indeed not work. thkala's solution may also work, but I find it less readable. It may be faster though, if you're doing a lot of find invocations.

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