转换HttpClient请求的URL中的&符号 [英] Escaping ampersands in URLs for HttpClient requests

问题描述

所以我有一些使用Jakarta HttpClient的Java代码，如下所示：

So I've got some Java code that uses Jakarta HttpClient like this:

URI aURI = new URI( "http://host/index.php?title=" + title + "&action=edit" );
GetMethod aRequest = new GetMethod( aURI.getEscapedPathQuery());

问题是如果标题包含任何&符号（&），它们被认为是参数分隔符，并且请求变得灵活...如果我用URL转义的等价物％26 替换它们，那么这将获得通过getEscapedPathQuery（）双重转义为％2526 。

The problem is that if title includes any ampersands (&), they're considered parameter delimiters and the request goes screwy... and if I replace them with the URL-escaped equivalent %26, then this gets double-escaped by getEscapedPathQuery() into %2526.

我正在通过基本修复损坏之后：

I'm currently working around this by basically repairing the damage afterward:

URI aURI = new URI( "http://host/index.php?title=" + title.replace("&", "%26") + "&action=edit" );
GetMethod aRequest = new GetMethod( aURI.getEscapedPathQuery().replace("%2526", "%26"));

但是，我有一个更好的方法来做到这一点吗？请注意，标题可以包含任何数量的不可预测的UTF-8字符等，所以逃避一切都是一个要求。

But there has to be a nicer way to do this, right? Note that the title can contain any number of unpredictable UTF-8 chars etc, so escaping everything else is a requirement.

推荐答案

你去：

import java.net.URLEncoder;
...
...
URI aURI = new URI( "http://host/index.php?title=" + URLEncoder.encode(title,"UTF-8") + "&action=edit" );
GetMethod aRequest = new GetMethod( aURI.getPathQuery());

检查 java.net.URLEncoder 获取更多信息。

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