在另一个进程退出时，在C＃中提升事件 [英] Raise event in C# when another process exits

问题描述

我不知道这个问题是否已经被问到，但是我找不到任何东西，所以如果你能找到一些东西，请带领我走正确的方向。

I don't know if this question was already asked, but I could not find anything on it, so please lead me in the right direction if you can find something.

基本上，我想在另一个指定的进程（example.exe）退出时，为当前的C＃程序添加一个事件。这是可能的吗？

Basically, I would like to add an event to my current C# program to be raised when another specified process ("example.exe") exits. Is that possible?

如果不可能，是否有一种方法来引导一个事件，当指定的进程通过直接路径（C：\somefolderpaths ... \example.exe）退出？

If that is not possible, is there, instead, a way to raise an event when a specified process by direct path ("C:\somefolderpaths...\example.exe") exits?

添加：我的程序不启动进程example.exe。

To add: My program does NOT start the process example.exe.

推荐答案

如果您使用C＃4.0，您可以执行以下操作：

If you are using C# 4.0 you can do something like:

 Task.Factory.StartNew(() => 
  { 
      var process = Process.Start("process.exe");
      process.WaitForExit();
  }).ContinueWith(

      //THE CODE THAT WILL RUN AFTER PROCESS EXITED.  

  ); 

编辑

如果您不是进程的创建者，则可以使用 Process.GetProcessesByName 函数从已经可用的方法中检索过程。

If you are not creator of a process, you can use Process.GetProcessesByName function to retrive the process from already available ones.

var process = Process.GetProcessesByName("process.exe");

通过这种方式，您可以避免阻止主线程，并在外部运行所需的代码进程退出同时，继续做一些更重要的事情。

In this way you can avoid blocking your main thread, and run the code you need at the moment external process exited. Meanwhile, continue do something more important.

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