C＃ - 覆盖事件处理程序 - 添加参数 [英] C# - Overriding an Event Handler - Adding a parameter

问题描述

我正在使用 System.Diagnostics.Process 类来执行命令行程序。

I'm using the System.Diagnostics.Process class to execute a command line program.

我我使用 OutputDataReceived 方法将输出重定向到我自己的方法。

I am using the OutputDataReceived method to redirect the output to my own method.

pr.OutputDataReceived += new DataReceivedEventHandler(OnDataReceived);
pr.ErrorDataReceived += new DataReceivedEventHandler(OnDataReceived);

但是，我有多个Threads运行这个cmd程序的多个实例。我想要做的是能够识别输出数据来自哪个流程实例 - 理想情况下，一个包含名称的字符串。 （每个进程在GUI上都有自己的进度条，我创建另一个事件来将输出传递给GUI，因此，我需要知道数据来自哪个进程来更新进度条）。

However, I have multiple Threads running multiple instances of this cmd program. What I want to do is to be able to identify which process instance the output data came from - ideally, a string containing a name. (Each process has it's own progress bar on a GUI. I create another event to pass the output to the GUI, thus, I need to know which process the data came from to update their progress bar).

我开始尝试：

public override delegate void DataReceivedEventHandler(object sender, DataReceivedEventArgs e, string processName);

然后我意识到我必须覆盖 OutputDataReceived 方法在Process类中。这反过来意味着我必须创建一个继承 System.Diagnostics.Process 的自定义类，并有一个接受字符串参数的方法，以便 OutputDataReceived 事件可以将流程实例名称（字符串）传递给我覆盖的 DataReceivedEventHandler 。

Then I realised that I would have to override the OutputDataReceived method inside the Process class. Which in turn would mean I have to create a custom class that inherits System.Diagnostics.Process, and have a method that accepts a string argument so the OutputDataReceived event can pass the process instance name (string) to my overridden DataReceivedEventHandler.

问题的目的是就如何进行一些意见。我建议什么似乎是完成我想要的正确方法？或者，有没有更好的方法来做？

The purpose of the question is to get some opinions on how to proceed. Does what I propose seem the right way to accomplish what I want? Or, is there a better way to do it?

推荐答案

你不能只使用 / code>对象传回并检查它正在运行的进程？

Can you not just use the sender object passed back and check which process it is running?

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