未报告的异常javax.script.ScriptException;必须被抓住或宣布被抛出 [英] Unreported exception javax.script.ScriptException; must be caught or declared to be thrown

问题描述

这是一个计算器应用程序。当我尝试编译它出现以下消息未报告的异常javax.script.ScriptException;必须被抓住或声明被抛出

我有一种感觉是因为该类设置为 ActionEvent 。我是一个学生，所以我还在学习：）

任何想法？感谢

\

解决方案

您可以执行以下操作： / p>

  // ..其他导入
 import javax.script.ScriptException; 
 
 // ..其余代码
 if（source == buteq）{
 try {
 ScriptEngineManager manager = new ScriptEngineManager（）; 
 ScriptEngine se = manager.getEngineByName（JavaScript）; 
 Object result = se.eval（createEquasion）; 
 finalAnswer = result.toString（）; 
 answer.setText（finalAnswer）; 
 catch（ScriptEngineManager e）{
 //处理异常
 System.err.println（评估脚本时出错+ e.getMessage（））; 
} 
} 
  

如果您正在处理任何类型的异常的方法，您可以在方法签名上添加 throws 声明：

  // ..其他导入
 import javax.script.ScriptException; 
 
 //你的方法签名
 public void actionPerformed（ActionEvent e）throws ScriptException {
 
 // ... 
 
 ScriptEngineManager manager = new ScriptEngineManager（）; 
 ScriptEngine se = manager.getEngineByName（JavaScript）; 
 Object result = se.eval（createEquasion）; 
 finalAnswer = result.toString（）; 
 answer.setText（finalAnswer）; 
 
 // ... 
  

应该是这样的。 >

This is a calculator App. When I try and compile it comes up with the following message unreported exception javax.script.ScriptException; must be caught or declared to be thrown

I have a feeling it is because the class is set as ActionEvent. I am a student so I am still learning :)

Any ideas? Thanks

\

解决方案

You can do the following:

// .. other imports
import javax.script.ScriptException;

// .. the rest of your code
if(source==buteq){
  try{
     ScriptEngineManager manager = new ScriptEngineManager();
     ScriptEngine se = manager.getEngineByName("JavaScript");        
     Object result = se.eval(createEquasion);
     finalAnswer = result.toString();
     answer.setText(finalAnswer);
  catch(ScriptEngineManager e) {
     // handle exception
     System.err.println("Error evaluating the script: " + e.getMessage());
  }
}

In case you are dealing with any kind of exception outside of the method you can add a throws declaration on your methods signature:

// .. other imports
import javax.script.ScriptException;

// your method signature
public void actionPerformed (ActionEvent e) throws ScriptException {

// ...

ScriptEngineManager manager = new ScriptEngineManager();
ScriptEngine se = manager.getEngineByName("JavaScript");        
Object result = se.eval(createEquasion);
finalAnswer = result.toString();
answer.setText(finalAnswer);

// ...

This should be it.

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