如何计算平均时间 [英] How to calculate average time

问题描述

如何计算的平均时间下午11点59分00秒和上午12:00:00，以便它可以是下午11时59分三十〇秒。目前这款code是给我上午11点59分三十○秒

  VAR convertTimeToMilliSecondsTest =功能（时间）{
                  VAR的startDate =1970/01/01;
       如果（time.indexOf（AM）！=  -  1）{
          NEWTIME = time.replace（AM，AM）;
       }否则如果（time.indexOf（PM）！=  -  1）{
          NEWTIME = time.replace（PM，PM）;
       }
          VAR dateString =的startDate ++ NEWTIME;
          VAR日期=新的日期（dateString.replace（/  -  /克，'/'））;
          返回date.getTime（）;
       }

         VAR calculateAverageTimeToBed =功能（数据集）{
                 变种totalTimeInMilliSeconds = 0;

                 对于（VAR I = 0; I＆LT; dataset.length ++我）{
                       totalTimeInMilliSeconds + = convertTimeToMilliSecondsTest（数据集[I] .startTime）;
                 }

                 VAR averageTimeInBed = totalTimeInMilliSeconds / dataset.length;

                 返回averageTimeInBed;
          }
 

解决方案

这是一个功能，如果你正在寻找给定一组时间，不论日期的平均时间，给出一个24小时的周期。它适用于上午12时 - 中午12点，但不是12点 - 凌晨12点（因为跨越2天）。如果你是跨天，你必须使用该方法要求在被评估的时间给予全日我第一个回答。

的jsfiddle

  //函数确定给定一组的平均时间
//在一个24小时的时间。期间，即上午12时 - 中午12点
//它不能用于24小时工作。期间中午12点 - 凌晨12点
无功倍= '11：59：00 AM'，'12：00：00 AM'];

//函数接受的时间数组作为参数
//需要时间的结构如上述
传播getAverageTime（次）{
    VAR数= times.length
    变种timesInSeconds = [];
    //通过次循环
    对于（VAR I = 0; I＆LT;计数;我++）{
        //解析
        VAR件=倍[I] .split（：）;
        变种的ampm =件[2] .split（''）;
        VAR小时数=（件[0]）;
        VAR分钟数=（件[1]）;
        变种秒=编号（的ampm [0]）;
        变种的ampm = AMPM [1];
        //转换为24小时格式（军用时间）
        如果（AMPM =='点'）小时=小时+ 12;
        在时间秒//寻找价值
        VAR totalSecs =小时* 60 * 60;
        totalSecs + =分钟* 60;
        totalSecs + =秒;
        //添加到阵列
        timesInSeconds [我] = totalSecs;
    }
    //发现平均timesInSeconds
    无功总= 0;
    执行console.log（timesInSeconds）;
    对于（VAR J = 0; J＆LT;计数; J ++）{
        总=总+数字（timesInSeconds [J]）;
    }
    VAR平均= Math.round（总/数）;
    的console.log（'平均秒：'+ AVG）;
    //转秒回一次
    VAR avgMins = Math.floor（平均/ 60）;
    VAR avgSecs =平均 - （60 * avgMins）;
    变种avgHrs = Math.floor（avgMins / 60）;
    的console.log（'时间：'+ avgHrs）;
    avgMins = avgMins  - （60 * avgHrs）;
    //转换回至12小时。格式
    VAR avgAmpm =AM;
    如果（avgHrs＆GT; 12）{
        avgAmpm ='PM';
        avgHrs = avgHrs  -  12;
    }
    //添加前导零秒，分钟
    avgSecs =（0+ avgSecs）.slice（-2）;
    avgMins =（0+ avgMins）.slice（-2）;
    // 你的回答
    返回avgHrs +：+ avgMins +：+ avgSecs +''+ avgAmpm;
}

// 执行
警报（getAverageTime（次））;
 

how to calculate average time with 11:59:00 PM and 12:00:00 AM so that it can be 11:59:30 PM. currently this code is giving me 11:59:30 AM

       var convertTimeToMilliSecondsTest = function(time) {
                  var startDate = "1970/01/01";                         
       if(time.indexOf("AM") != -1) {
          newTime = time.replace("AM", " AM");
       } else if(time.indexOf("PM") != -1) {
          newTime = time.replace("PM", " PM");
       }
          var dateString = startDate + " " + newTime;
          var date = new Date(dateString.replace(/-/g, '/'));                                 
          return date.getTime();
       }

         var calculateAverageTimeToBed = function(dataset) {
                 var totalTimeInMilliSeconds = 0;

                 for(var i = 0;i < dataset.length; ++i) {
                       totalTimeInMilliSeconds += convertTimeToMilliSecondsTest(dataset[i].startTime);
                 }

                 var averageTimeInBed = totalTimeInMilliSeconds / dataset.length;

                 return averageTimeInBed;
          }

解决方案

This is a function for if you are looking for an average time given a set of times, regardless of date, given a 24 hr period. It works for 12am - 12pm but not 12pm - 12am (because that spans 2 days). If you are spanning days, you must use my first answer which requires the entire date be given in the time being evaluated.

jsFiddle

// function will determine average time given a set of 
// times in a 24 hr. period, i.e. 12am - 12pm
// it does NOT work for a 24 hr. period from 12pm - 12am
var times = ['11:59:00 AM', '12:00:00 AM'];

// function accepts an array of times as the argument
// requires time to be structured as above
function getAverageTime(times) {
    var count = times.length
    var timesInSeconds = [];
    // loop through times
    for (var i =0; i < count; i++) {
        // parse
        var pieces = times[i].split(':');
        var ampm = pieces[2].split(' ');
        var hrs = Number(pieces[0]);
        var mins = Number(pieces[1]);
        var secs = Number(ampm[0]);
        var ampm = ampm[1];
        // convert to 24 hr format (military time)
        if (ampm == 'PM') hrs = hrs + 12;   
        // find value in seconds of time
        var totalSecs = hrs * 60 * 60;
        totalSecs += mins * 60;
        totalSecs += secs;
        // add to array
        timesInSeconds[i] = totalSecs;
    }
    // find average timesInSeconds
    var total = 0;
    console.log(timesInSeconds);
    for (var j =0; j < count; j++) {
        total = total + Number(timesInSeconds[j]);
    }
    var avg = Math.round(total / count);
    console.log('avg secs: '+avg);
    // turn seconds back into a time
    var avgMins = Math.floor(avg/60);
    var avgSecs = avg - (60 * avgMins);
    var avgHrs = Math.floor(avgMins/60);
    console.log('hours: '+avgHrs);
    avgMins = avgMins - (60 * avgHrs);
    // convert back to 12 hr. format
    var avgAmpm = 'AM';
    if (avgHrs > 12) {
        avgAmpm = 'PM';
        avgHrs = avgHrs - 12;
    }
    // add leading zeros for seconds, minutes
    avgSecs = ('0' + avgSecs).slice(-2);
    avgMins = ('0' + avgMins).slice(-2);
    // your answer
    return avgHrs+':'+avgMins+':'+avgSecs+' '+avgAmpm;
}

// execute
alert(getAverageTime(times));

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