Python 一段代码遇到问题

问题描述

问 题

def check_connection(network,name1,name2):
    network = list(network)
    name = name1
    for a in network:
        if name in a and name2 in a:
            print 'yes'
            return True
    for a in network:
        if name in a:
            name = a.replace(name1,'').replace('-','')
            network.remove(a)
            check_connection(network,name,name2)
    return False

print check_connection(("dr101-mr99", "mr99-out00", "dr101-out00", "scout1-scout2","scout3-scout1", "scout1-scout4", "scout4-sscout", "sscout-super"),"super", "scout2")

输出：

yes
False

明明 return True 了，为什么最后的结果是 False ？
麻烦大家了，我是一名Python自学者，还不太会提问题，请见谅！

解决了：

def check_connection(network,name1,name2):
    network = list(network)
    for a in network:
        if name1 in a and name2 in a:
            return True
    for a in network:
        if name1 in a:
            name1 = a.replace(name1,'').replace('-','')
            network.remove(a)
            return check_connection(network,name1,name2) 
    return False

提示：递归函数，return 只是跳出递归函数

这个问题已被关闭，原因：问题已解决 - 问题已解决，且对他人无借鉴意义

解决方案

def check_connection(network,name1,name2):
    network = list(network)
    for a in network:
        if name1 in a and name2 in a:
            return True
    for a in network:
        if name1 in a:
            name1 = a.replace(name1,'').replace('-','')
            network.remove(a)
            return check_connection(network,name1,name2) 
    return False

递归函数

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