php - nginx日志正则格式怎么转换成apache日志格式

问题描述

问 题

nginx日志格式

log_format  access  '$remote_addr - [$time_local] "$request" '
             '$status $body_bytes_sent $request_time "$http_referer" '
             '"$http_user_agent" - $http_x_forwarded_for';

以下是nginx的日志正则提取格式

log_pattern = r'^(?P<remote_addr>.*?) - \[(?P<time_local>.*?)\] "(?P<request>.*?)"' \
              r' (?P<status>.*?) (?P<body_bytes_sent>.*?) (?P<request_time>.*?)' \
              r' "(?P<http_referer>.*?)" "(?P<http_user_agent>.*?)" - (?P<http_x_forwarded_for>.*)$'

request_uri_pattern = r'^(?P<request_method>(GET|POST|HEAD|DELETE)?) (?P<request_uri>.*?) (?P<server_protocol>HTTP.*)$'

我的Apache日志格式如下：

123.125.71.55 - - [14/Apr/2017:00:00:15 +0800] "GET /article/511615 HTTP/1.1" 200 11238
111.206.221.100 - - [14/Apr/2017:00:00:16 +0800] "POST /baidutj/tj HTTP/1.1" 302 -

怎么把上面的正则修改成我能用的正则，

自己尝试了好久 一直出错，

解决方案

log_pattern = (r'^(?P<remote_addr>\S+) - - \[(?P<time_local>[^]]+)\] "(?P<request>.*?)"'
              ' (?P<status>\d+) (?P<body_bytes_sent>\d+)')
request_uri_pattern = r'"(?P<request_method>(?:GET|POST|HEAD|DELETE)?) (?P<request_uri>\S*) (?P<server_protocol>HTTP\S*?")'

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