javascript - 函数优化方法

问题描述

问 题

以下函数有点长，请问有什么方法可以优化一下

        _loadSumListData : function(data){
            var total_revenue ;
            var free_revenue;
            var billing_revenue;
            var channel_total_revenue;
            var channel_revenue;
            if ( data.total_revenue == null ) {
                total_revenue = "-";
            } else {
                total_revenue = moneyFormat._formatMoney(data.total_revenue);
            };
            if ( data.free_revenue == null ) {
                free_revenue = "-";
            } else {
                free_revenue = moneyFormat._formatMoney(data.free_revenue);
            };
            if ( data.billing_revenue == null ) {
                billing_revenue = "-";
            } else {
                billing_revenue = moneyFormat._formatMoney(data.billing_revenue);
            };
            if (data.channel_total_revenue == null ) {
                channel_total_revenue =  "-";
            } else {
                channel_total_revenue = moneyFormat._formatMoney(data.channel_total_revenue);
            };
            if (data.channel_revenue == null ) {
                channel_revenue =  "-";
            } else {
                channel_revenue = moneyFormat._formatMoney(data.channel_revenue);
            };
            var sumList = "<td align='center'>"+total_revenue+"</td><td align='center'>"+free_revenue+"</td><td align='center'>"+billing_revenue+"</td><td align='center'>"
            +channel_total_revenue+"</td><td align='center'>"+channel_revenue+"</td>";
           $(".sum-list-table tbody").append(sumList);
        }

解决方案

_loadSumListData : function (data) {
    var sumList = '';
    $.each(['total_revenue', 'free_revenue', 'billing_revenue', 'channel_total_revenue'], function (index, item) {
        sumList += "<td align='center'>" + (item ? moneyFormat._formatMoney(item) : '-') + "</td>";
    })
    $(".sum-list-table tbody").append(sumList);
}

这篇关于javascript - 函数优化方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！