编程注册的广播接收器 [英] Programmatically register a broadcast receiver

问题描述

我想知道什么是编程方式注册的广播接收器的最佳实践/方法。我想注册特定的接收器可根据用户的选择。

I'd like to know what is the best practice/way of programmatically register a broadcast receiver. I want to register specific receivers according to user choice.

作为注册是通过清单文件做了，我不知道是否有一个适当的方式在code来实现这一点。

As the registration is done through the manifest file, I'm wondering if there's a proper way to achieve this in code.

推荐答案

这听起来像你想控制的组件是否刊登在你的清单是积极的，而不是动态注册一个接收器（通过Context.registerReceiver（））在运行。

It sounds like you want to control whether components published in your manifest are active, not dynamically register a receiver (via Context.registerReceiver()) while running.

如果是这样，你可以使用PackageManager.setComponentEnabledSetting（）来控制这些设备是否处于活动状态：

If so, you can use PackageManager.setComponentEnabledSetting() to control whether these components are active:

<一个href="http://developer.android.com/reference/android/content/pm/PackageManager.html#setComponentEnabledSetting%28android.content.ComponentName,%20int,%20int%29">http://developer.android.com/reference/android/content/pm/PackageManager.html#setComponentEnabledSetting(android.content.ComponentName, INT，INT）

请注意，如果你只关注接收广播你正在运行时，最好是使用registerReceiver（）。接收机组件是当你需要确保你的应用程序是广播发送，每次推出的主要是有用的。

Note if you are only interested in receiving a broadcast while you are running, it is better to use registerReceiver(). A receiver component is primarily useful for when you need to make sure your app is launched every time the broadcast is sent.

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