Swift中的try-catch异常 [英] try-catch exceptions in Swift

问题描述

是否可以在Swift中捕获异常？给出以下代码：

Is it possible to catch exceptions in Swift? Given the following code:

NSException.raise(NSRangeException,
    format: "Now you've gone too far!",
    arguments: CVaListPointer(fromUnsafePointer: UnsafePointer()))

是否可以防止异常崩溃整个程序？也就是说，在Objective-C中Swift等同于以下内容：

Is it possible to prevent the exception from crashing the entire program? That is, what is the Swift equivalent of the following in Objective-C:

@try {
    [NSException raise:NSRangeException format:@"Now you've gone too far!"];
}

推荐答案

它没有异常处理，和开发人员论坛中的这个讨论讨论了为什么会这样：

但请记住，Cocoa和Cocoa Touch传统上并不打算
来捕捉异常;他们打算不要让他们首先抛出
。应该使用
可选类型和inout NSError参数来处理普通错误;你应该解决任何
的情况，导致断言失败（这似乎是Swift中唯一的
异常抛出机制）通过编写更好的代码。

but keep in mind that Cocoa and Cocoa Touch traditionally don't intend for you to catch exceptions; they intend for you to not cause them to be thrown in the first place. Ordinary errors should be handled with optional types and inout NSError parameters; you should address any situation that causes an assertion to fail (which seems to be the only exception-throwing mechanism in Swift) by writing better code.

这篇关于Swift中的try-catch异常的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！