Python：如何忽略异常并继续？ [英] Python: How to ignore an exception and proceed?

问题描述

我有一个尝试...除了我的代码中的块，当一个异常是抛出。我真的只想继续使用代码，因为在这种情况下，一切仍然能够运行。问题是如果你将except：block留空或#do没有，它会给你一个语法错误。我不能使用继续，因为它不在循环。有没有一个可以使用的关键字，告诉代码呢？

I have a try...except block in my code and When an exception is throw. I really just want to continue with the code because in that case, everything is still able to run just fine. The problem is if you leave the except: block empty or with a #do nothing, it gives you a syntax error. I can't use continue because its not in a loop. Is there a keyword i can use that tells the code to just keep going?

推荐答案

except:
    pass

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