正则表达式：查找范围，除了一个字母或范围 [英] Regular expression: find range except for one letter or a range

问题描述

如何使用方括号内的否定作为例外，找到e。 G。 a-z之间的一切除了m-o的范围之外？ [az ^ mo] ？

提前感谢！

顺便说一下：我不是为了这个例子而是要求，而是能够在范围内排除范围，甚至排除范围内的单个字母。我非常清楚，在这个例子中，它可以被计算...;）再次感谢你提前！

我使用Zend引擎（PHP） / p>

解决方案

你应该可以自己计算差价。

  [a-lp-z] 
  

如果正则表达式引擎支持先知断言，您可以使用

 （？！[mo]）[az] 
  / pre> 
 
 
但这可能效率较低。
 
How can I use the negation within square brackets as an exception, to find e. g. everything between a-z except for the the range from m-o? [a-z^m-o]?

Thanks in advance!

By the way: it's not for the sake of this example that I ask, but to be able to exclude ranges within ranges, or even single letters within ranges. I am pretty much aware that in this example it can be calculated... ;) Once again, thanks in advance!

I use the Zend engine (PHP).
解决方案
You should be able calculate the difference yourself.
[a-lp-z]
If the regex engine supports lookahead assertion, you could use
(?![m-o])[a-z]
but this would probably be less efficient.

                        
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