当引发异常时，设置Python中的退出代码 [英] Setting exit code in Python when an exception is raised

问题描述

$ cat e.py
raise Exception
$ python e.py
Traceback (most recent call last):
  File "e.py", line 1, in <module>
    raise Exception
Exception
$ echo $?
1

我想将此退出代码从1更改为3，同时仍然将全堆栈跟踪。这是最好的方法？

I would like to change this exit code from 1 to 3 while still dumping the full stack trace. What's the best way to do this?

推荐答案

看看 traceback 模块。您可以执行以下操作：

Take a look at the traceback module. You could do the following:

import sys, traceback

try:
  raise Exception()
except:
  traceback.print_exc()
  sys.exit(3)

这将写回溯到标准错误，并退出与代码3。

This will write traceback to standard error and exit with code 3.

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