Java ConcurrentModificationException [英] Java ConcurrentModificationException

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本文介绍了Java ConcurrentModificationException的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

当删除第二个元素时,没有ConcurrentModificationException

when remove the second last element there is no ConcurrentModificationException

List<String> myList1 = new ArrayList<String>();
Collections.addAll(myList1, "str1","str2","str3","str4","str5");
for(String element : myList1){//no ConcurrentModificationException here
if(element.equalsIgnoreCase("str4"))
    myList1.remove("str4");
}
System.out.println(myList1);

但是当删除其他元素时,会出现一个ConcurrentModificationException

But when remove other elements there is a ConcurrentModificationException

List<String> myList2 = new ArrayList<String>();
Collections.addAll(myList2, "str1","str2","str3","str4","str5");
for(String element : myList2){//ConcurrentModificationException here
if(element.equalsIgnoreCase("str1"))
    myList2.remove("str1");
}
System.out.println(myList2);

原因是什么?

推荐答案

我看到同样的事情,

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class Launcher 
{
    public static void main(String[] args) 
    {
        doThis();
        doThat();
    }

    private static void doThis()
    {
        System.out.println("dothis");
        try
        {
            List<String> myList1 = new ArrayList<String>();
            Collections.addAll(myList1, "str1","str2","str3","str4","str5");
            for(String element : myList1){//no ConcurrentModificationException here
            if(element.equalsIgnoreCase("str4"))
                myList1.remove("str4");
            }
            System.out.println(myList1);
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
    }

    private static void doThat()
    {
        System.out.println("dothat");
        try
        {
            List<String> myList2 = new ArrayList<String>();
            Collections.addAll(myList2, "str1","str2","str3","str4","str5");
            for(String element : myList2){//ConcurrentModificationException here
            if(element.equalsIgnoreCase("str1"))
                myList2.remove("str1");
            }
            System.out.println(myList2);
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
    }
}

哪些输出,

dothis
[str1, str2, str3, str5]
dothat
java.util.ConcurrentModificationException
    at java.util.AbstractList$Itr.checkForComodification(Unknown Source)
    at java.util.AbstractList$Itr.next(Unknown Source)
    at com.foo.Launcher.doThat(Launcher.java:41)
    at com.foo.Launcher.main(Launcher.java:12)



< hr>

我发现 原因

这篇关于Java ConcurrentModificationException的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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