如何抑制（.net）异常对象的创建？ [英] How to supress the creation of an (.net) Exception object?

问题描述

如果我不在乎抛出异常。我可以用某种方式编写代码来创建它吗？

If I do not care about a thrown Exception. Can I code in a way as not to create it?

换句话说，可以抛出异常，但是不会创建Exception对象？

In other words, can an Exception be thrown but no Exception object be created?

一个例子 - 使用System.Net.Sockets.Socket的简单示例

An example - Simple example using a System.Net.Sockets.Socket

 Socket acceptingSocket;
acceptingSocket.Blocking = false;

while(condition)
{
    try
    {
        Socket acceptedSocket = acceptingSocket.Accept(); //(i)
        doWork(acceptedSocket);
    }
    catch{}
}

因为套接字在非阻塞模式
如果没有连接接受
a SocketException抛出在点（i）
和条件循环继续。

because the socket is in non-blocking mode if there is no connection to accept a SocketException is thrown at point (i) and the conditional loop continues.

使用这个代码实现 - 将创建SocketException对象？

using this code implementation - will the SocketException object be created?

如果它被创建 - 有没有办法不创建它？

AND if it is created - is there a way to NOT create it?

推荐答案

你不能抑制异常，你只能忽略它们。在任何情况下，它不是创建异常对象是昂贵的 - 这是抛出异常时发生的堆栈步骤。

You can't suppress exceptions, you can only ignore them. In any case, it's not the creating of the Exception object that's expensive -- it's the stack walk that happens when the exception is thrown.

另外，

catch(SocketException) {}

不是

catch { } or catch(Exception) { }

：）

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