在C＃中简单的LINQ问题 [英] Simple LINQ question in C#

问题描述

我想使用 LINQ 返回其发生的时间和最大数量发生的次数的一个元素。

例如： 我有一个字符串数组：

 的String []字= {樱桃，苹果，蓝莓，樱花，樱花，蓝莓};

// ...
这里有些LINQ声明
// ...
 

在此阵列，查询将返回樱桃作为最大发生的元素，而 3 的数量有时它发生。我也愿意将它们分成两个查询，如果这是必要的（即的第一次查询，以获得樱桃，和第二返回计数 3 。

解决方案

  VAR topWordGroup = words.GroupBy（字=＆GT;字）.OrderByDescending（组=＆GT; group.Count（ ））FirstOrDefault（）。
// topWordGroup可能是空的！
字符串topWord = topWordGroup.Key;
INT topWordCount = topWordGroup.Count;
 

和的情况下，如果我们不喜欢 O（N日志N）：

  VAR topWordGroup = words.GroupBy（字=＆GT;字）.Aggregate（（电流，ACC）=＆GT; current.Count（）＆LT; acc.Count（）ACC ： 当前）;
 

I am trying to use LINQ to return the an element which occurs maximum number of times AND the number of times it occurs.

For example: I have an array of strings:

string[] words = { "cherry", "apple", "blueberry", "cherry", "cherry", "blueberry" };

//...
Some LINQ statement here
//...

In this array, the query would return cherry as the maximum occurred element, and 3 as the number of times it occurred. I would also be willing to split them into two queries if that is necessary (i.e., first query to get the cherry, and second to return the count of 3.

解决方案

var topWordGroup = words.GroupBy(word => word).OrderByDescending(group => group.Count()).FirstOrDefault();
// topWordGroup might be a null!
string topWord = topWordGroup.Key;
int topWordCount = topWordGroup.Count;

And in case if we don't like O(N log N):

var topWordGroup = words.GroupBy(word => word).Aggregate((current, acc) => current.Count() < acc.Count() ? acc : current);

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