Java - 如何检查抛出哪种异常类型？ [英] Java - How to check which exception type was thrown?

问题描述

如果操作捕获多个异常，我如何确定捕获哪种类型的异常？

How can I determine which type of exception was caught, if an operation catches multiple exceptions?

这个例子应该更有意义：

This example should make more sense:

try {
  int x = doSomething();
} catch (NotAnInt | ParseError e) {
  if (/* thrown error is NotAnInt */) {    // line 5
    // printSomething
  } else {
    // print something else
  }
}

第5行，我可以检查哪个异常被捕获？

On line 5, how can I check which exception was caught?

我试过 if（e.equals（NotAnInt.class））{..} 但没有运气。

注意： NotAnInt 和 ParseError 是我的项目中的类，扩展异常。

NOTE: NotAnInt and ParseError are classes in my project that extend Exception.

推荐答案

如果您不能将这两种情况分别放在 catch 块中，请使用：

If you can't put the two cases in separate catch blocks, use:

if (e instanceof NotAnInt) {
    ...
}

which is sometimes justified, like when you need shared logic for 2 or more different exception classes.

否则，使用单独的 catch 块：

} catch (NotAnInt e) {
    ...
} catch (ParseError e) {
    ...
}

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