Android的碎片没有查看发现的ID？ [英] Android Fragment no view found for ID?

问题描述

我有一个片段，我想加入到一个视图。

I have a fragment I am trying to add into a view.

FragmentManager fragMgr=getSupportFragmentManager();
feed_parser_activity content = (feed_parser_activity)fragMgr
                                    .findFragmentById(R.id.feedContentContainer);
FragmentTransaction xaction=fragMgr.beginTransaction();

if (content == null || content.isRemoving()) {
    content=new feed_parser_activity(item.getLink().toString());
    xaction
        .add(R.id.feedContentContainer, content)
        .setTransition(FragmentTransaction.TRANSIT_FRAGMENT_OPEN)
        .addToBackStack(null)
        .commit();
    Log.e("Abstract", "DONE");
}

在执行此code，我得到以下错误调试。

When this code is executed I get the following error in debug..

java.lang.IllegalArgumentException: No view found for id 0x7f080011 
   for fragment feed_parser_activity{41882f50 #2 id=0x7f080011}

feed_pa​​rser_activity 是设置为XML片段布局中的片段。
我使用的是FragmentActivity主办的片段布局保持了 feed_pa​​rser_layout 。
我是不是该编码上述正确？

feed_parser_activity is a Fragment that is set to Fragment layout in xml.
I am using a FragmentActivity to host the Fragment Layout holding the feed_parser_layout.
Am I coding this correctly above?

推荐答案

我是有这个问题太多，直到我意识到，我已经指定了的setContentView错误的布局（）的onCreate（）法>

I was having this problem too, until I realized that I had specified the wrong layout in setContentView() of the onCreate() method of the FragmentActivity.

传入 FragmentTransaction.add的ID（），你的情况 R.id.feedContentContainer ，必须）在的setContentView（指定的布局。

The id passed into FragmentTransaction.add(), in your case R.id.feedContentContainer, must be a child of the layout specified in setContentView().

您没有向我们展示你的的onCreate（）的方法，所以这也许是同样的问题。

You didn't show us your onCreate() method, so perhaps this is the same problem.

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