在python脚本中设置环境变量 [英] set environment variable in python script

问题描述

我有一个bash脚本设置一个环境变量运行一个命令

  LD_LIBRARY_PATH = my_path 
 sqsub  - np $ 1 / homedir / anotherdir / executable 
  

现在我想使用python而不是bash，因为我想计算我传递命令的一些参数。

我尝试过

  putenv（LD_LIBRARY_PATH，my_path）
  

和

  call（export LD_LIBRARY_PATH = my_path）
  

后跟

  call（sqsub -np+ var1 +/ homedir / anotherdir /可执行文件）
  

但总是程序放弃，因为LD_LIBRARY_PATH未设置。

如何解决这个问题？

感谢您的帮助！

如果我在调用python脚本之前导出LD_LIBRARY_PATH，一切都可行，但是我希望python来确定路径并设置en veroment变量为正确值）

解决方案

bash：

  LD_LIBRARY_PATH = my_path 
 sqsub -np $ 1 / path / to / executable 
  

类似于Python：

  import os 
 import subprocess 
 import sys 
 
 os.environ ['LD_LIBRARY_PATH'] =my_path＃在此进程中可见*所有子项
 subprocess.check_call（['sqsub'，'-np'，sys.argv [1] '/ path / to / executable']，
 env = dict（os.environ，SQSUB_VAR =在此子进程中可见）
  

I have a bash script that sets an environment variable an runs a command

LD_LIBRARY_PATH=my_path
sqsub -np $1 /homedir/anotherdir/executable

Now I want to use python instead of bash, because I want to compute some of the arguments that I am passing to the command.

I have tried

putenv("LD_LIBRARY_PATH", "my_path")

and

call("export LD_LIBRARY_PATH=my_path")

followed by

call("sqsub -np " + var1 + "/homedir/anotherdir/executable")

but always the program gives up because LD_LIBRARY_PATH is not set.

How can I fix this?

Thanks for help!

(if I export LD_LIBRARY_PATH before calling the python script everything works, but I would like python to determine the path and set the environment variable to the correct value)

解决方案

bash:

LD_LIBRARY_PATH=my_path
sqsub -np $1 /path/to/executable

Similar, in Python:

import os
import subprocess
import sys

os.environ['LD_LIBRARY_PATH'] = "my_path" # visible in this process + all children
subprocess.check_call(['sqsub', '-np', sys.argv[1], '/path/to/executable'],
                      env=dict(os.environ, SQSUB_VAR="visible in this subprocess"))

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