如何在Node.js和Express 4上分离路由？ [英] How to separate routes on Node.js and Express 4?

问题描述

我想从我的server.js文件中分离路由。

I want to separate Routes from my server.js file.

我正在关注Scotch.io的这个教程
http://scotch.io/tutorials/javascript/build-a-restful-api-using-node-and-express-4

I am following this tutorial on Scotch.io http://scotch.io/tutorials/javascript/build-a-restful-api-using-node-and-express-4

如果所有行都在server.js文件上，它正在工作。但我没有分开。如何使这项工作？

It is working if all lines are on server.js file. But I am failing to separate. How can I make this work?

server.js

server.js

// set up ======================================================================
var express = require('express');
var app = express();
var bodyParser = require('body-parser');

// configuration ===============================================================
app.use(bodyParser());

var port = process.env.PORT || 8000;

var mongoose = require('mongoose');
var database = require('./config/database');
mongoose.connect(database.url);
var Video = require('./app/models/video');

// routes =======================================================================
app.use('/api', require('./app/routes/routes').router);

// listen (start app with node server.js) ======================================
app.listen(port);
console.log("ready captain, on deck" + port);

module.exports = app;

而app / routes / routes.js

And the app/routes/routes.js

var express = require('express');
var router = express.Router();

router.use(function(req, res, next) {
  console.log('Something is happening.');
  next();
});

router.get('/', function(req, res) {
  res.json({ message: 'hooray! welcome to our rest video api!' });  
});


router.route('/videos')

  .post(function(req, res) {

    var video = new Video();
    video.title = req.body.title;

    video.save(function(err) {
  if (err)
    res.send(err);

  res.json({ message: 'Video criado!' });
});


  })

  .get(function(req, res) {
    Video.find(function(err, videos) {
      if (err)
        res.send(err);

      res.json(videos);
    });
  });

module.exports.router = router;

推荐答案

只要从主文件分离路由。 。

As far as separating routes from main file is concerned..

Server.js

//include the routes file
var routes = require('./routes/route');
var users = require('./routes/users');
var someapi = require('./routes/1/someapi');

////////
app.use('/', routes);
app.use('/users', users);
app.use('/1/someapi', someapi);

routes / route.js

//last line - try this
module.exports = router;

另外对于新项目，您可以在命令行中尝试

Also for new project you can try on command line

express project_name

您将需要快速生成器为此

You will need express-generator for that

这篇关于如何在Node.js和Express 4上分离路由？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！