在root之后通过可选参数传递路由控制？ [英] Passing route control with optional parameter after root in express?

问题描述

我正在开发一个简单的URL缩短应用程序，并具有以下快速路线：

I'm working on a simple url-shortening app and have the following express routes:

app.get('/', function(req, res){
  res.render('index', {
    link: null
  });
});

app.post('/', function(req, res){
  function makeRandom(){
    var text = "";
    var possible = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";

    for( var i=0; i < 3 /*y u looking at me <33??*/; i++ )
      text += possible.charAt(Math.floor(Math.random() * possible.length));
    return text;
  }
  var url = req.body.user.url;
  var key = makeRandom();
  client.set(key, url);
  var link = 'http://50.22.248.74/l/' + key;
  res.render('index', {
    link: link
  });
  console.log(url);
  console.log(key);
});

app.get('/l/:key', function(req, res){
  client.get(req.params.key, function(err, reply){
    if(client.get(reply)){
      res.redirect(reply);
    }
    else{
      res.render('index', {
        link: null
      });
    }
  });
});

我想删除 / l / 从我的路线（使我的URL更短），并使：key参数可选。这将是正确的方法：

I would like to remove the /l/ from my route (to make my url's shorter) and make the :key parameter optional. Would this be the correct way to do this:

app.get('/:key?', function(req, res, next){
  client.get(req.params.key, function(err, reply){
    if(client.get(reply)){
      res.redirect(reply);
    }
    else{
      next();
    }
  });
});

app.get('/', function(req, res){
  res.render('index, {
    link: null
  });
});

不知道如果我需要指定我的 / 路由是要nexted的路由。但是，由于我唯一的其他路线将是我更新的帖子 / route，我可以想象它会正常运行。

Not sure if I need to specify that my / route is the one to be "nexted" to. But since my only other route would be my updated post / route, I would imagine it would work fine.

推荐答案

这个工作方式取决于client.get作为其第一个参数传递时所做的定义。

That would work depending on what client.get does when passed undefined as its first parameter.

这样做会更安全：

app.get('/:key?', function(req, res, next) {
    var key = req.params.key;
    if (!key) {
        next();
        return;
    }
    client.get(key, function(err, reply) {
        if(client.get(reply)) {
            res.redirect(reply);
        }
        else {
            res.render('index', {
                link: null
            });
        }
    });
});

在回调内调用next（）没有问题。

There's no problem in calling next() inside the callback.

根据此，处理程序按照以下顺序调用：它们被添加，所以只要你的下一个路由是app.get（'/'，...）它将被调用，如果没有密钥。

According to this, handlers are invoked in the order that they are added, so as long as your next route is app.get('/', ...) it will be called if there is no key.

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